1
我最近遇到了下面的函数来在计算器:执行一个功能。无法打印输出
CREATE FUNCTION dbo.UrlDecode(@url varchar(3072))
RETURNS varchar(3072)
AS
BEGIN
DECLARE @count int, @c char(1), @cenc char(2), @i int, @urlReturn varchar(3072)
SET @count = Len(@url)
SET @i = 1
SET @urlReturn = ''
WHILE (@i <= @count)
BEGIN
SET @c = substring(@url, @i, 1)
IF @c LIKE '[!%]' ESCAPE '!'
BEGIN
SET @cenc = substring(@url, @i + 1, 2)
SET @c = CHAR(CASE WHEN SUBSTRING(@cenc, 1, 1) LIKE '[0-9]'
THEN CAST(SUBSTRING(@cenc, 1, 1) as int)
ELSE CAST(ASCII(UPPER(SUBSTRING(@cenc, 1, 1)))-55 as int)
END * 16 +
CASE WHEN SUBSTRING(@cenc, 2, 1) LIKE '[0-9]'
THEN CAST(SUBSTRING(@cenc, 2, 1) as int)
ELSE CAST(ASCII(UPPER(SUBSTRING(@cenc, 2, 1)))-55 as int)
END)
SET @urlReturn = @urlReturn + @c
SET @i = @i + 2
END
ELSE
BEGIN
SET @urlReturn = @urlReturn + @c
END
SET @i = @i +1
END
RETURN @urlReturn
END
GO
I am trying to pass the following URL as an input to get the decoded URL as output using the following command:
DECLARE @urlReturn nvarchar(3072);
EXEC dbo.UrlDecode2 @url = 'https%3a%2f%2fin.mathworks.com';
PRINT @urlReturn;
GO
最初尝试了以下内容:
exec dbo.UrlDecode2 @url = 'https%3a%2f%2fin.mathworks.com';
go
功能的URL解码编码的部分。我对PL/SQL完全陌生。有人能告诉我我哪里出错了,以及如何打印解码的URL。
请正确格式化你的代码。您可以通过将每行缩进4个空格或突出显示代码并按ctrl + k来完成此操作。 – Carcigenicate
代码是如此清晰的SQL Server,我删除了PL/SQL标签。如果你真的使用Oracle,你应该让自己有另一个功能。 –