2014-12-06 46 views
0

我一直在为简单的iOS用户系统开发Web服务。 PHP查询完美,但有一个问题 - iOS工作不太好。数据未收到。我如何继续?这是我的连接类:iOS连接不返回数据

import Foundation 

class Connection: NSObject { 
    var data: NSMutableData = NSMutableData() 

    func login(username: String, password: String) { 
     var url: NSURL = NSURL(string: "localhost/getusers.php?username=" + username + "&password=" + password)! 
     var request: NSURLRequest = NSURLRequest(URL: url) 
     var conn: NSURLConnection = NSURLConnection(request: request, delegate: self, startImmediately: true)! 
    } 

    func connection(didReceiveResponse: NSURLConnection!, didReceiveResponse response: NSURLResponse!) { 
     println("didReceiveResponse") 
    } 

    func connection(connection: NSURLConnection!, didReceiveData conData: NSData!) { 
     self.data.appendData(conData) 
    } 

    func connectionDidFinishLoading(connection: NSURLConnection!) { 
     println(self.data) 
    } 

    deinit { 
     println("deiniting") 
    } 
} 

这里它被称为地方。

@IBAction func attemptLogin(sender: UIButton) { 
     if(usernameTextField.text == "" || passwordTextField.text == "") { 
      var alert = UIAlertController(title: "Error", message: "Invalid Credentials", preferredStyle: UIAlertControllerStyle.Alert) 
      alert.addAction(UIAlertAction(title: "Close", style: UIAlertActionStyle.Default, handler: nil)) 
      self.presentViewController(alert, animated: true, completion: nil) 

      var connection: Connection = Connection() 
      connection.login(usernameTextField.text, password: passwordTextField.text) 
     } 
    } 

最后,这里的PHP服务:

error_reporting(E_ALL); 
ini_set('display errors', 1); 

$username = 'root'; 
$password = 'root'; 

try { 
    $DBH = new PDO('mysql:host=localhost; dbname=login_test', $username, $password); 
    $DBH->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 

    $recievedUsername = $_GET['username']; 
    $recievedPassword = $_GET['password']; 

    $data = array($recievedUsername, $recievedPassword); 

    $STH = $DBH->prepare("SELECT id, first_name, last_name FROM `users` WHERE `username` = ? AND `password` = ?"); 
    $STH->execute($data); 

    $row = $STH->fetch(PDO::FETCH_ASSOC); 
    echo json_encode($row); 
} catch(PDOException $e) { 
    echo $e->getMessage(); 
} 

回答

0

嗯,我看到将是你没有实现NSURLConnectionDelegate上您的课嘛....应该是

class Connection: NSObject, NSURLConnectionDelegate {...} 

可能非NSURLConnection的委托方法当前被调用吗?你检查过了吗?

+1

'NSURLConnectionDelegate'是一种罕见的鸭子类型的代表 - 参数仅仅是类型为'AnyObject',所以你不一定需要*声明*符合您的委托方法被调用(虽然这是一个很好的做法)。 – 2014-12-06 20:02:08

+0

经过测试,它们都运行。 – Jeffrey 2014-12-06 21:47:38

1

你在编译过的应用程序中试过这个吗?你的代码在这种情况下适用于我。

一旦游戏场到达代码末尾就会停止运行,所以没有任何异步调用返回。为了使操场上继续运行,导入XCPlayground这行添加到底层:

XCPSetExecutionShouldContinueIndefinitely() 
+0

是的,我已经在应用程序中试过了,但没有任何东西被控制台输出。 – Jeffrey 2014-12-06 21:48:21