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我有一个XML文档如下:递归解析XMLDOCUMENT
<directory>
<file><monitored>0</monitored>
<xferStatus>1</xferStatus>
<name>test1.txt</name>
<size>7</size>
<created>03/31/10 11:30:02 AM</created>
<modified>03/31/10 11:30:00 AM</modified>
<tPathList><tPath>http://hwcdn.net/p2f4h2b5/cds/testing/test1.txt</tPath>
</tPathList>
<tPath>http://hwcdn.net/p2f4h2b5/cds/testing/test1.txt</tPath>
<oPathList><oPath>http://hwcdn.net/p2f4h2b5/w9m3i4q9/test1.txt</oPath>
</oPathList>
<oPath>http://hwcdn.net/p2f4h2b5/w9m3i4q9/test1.txt</oPath>
<aPath></aPath>
</file>
<file><monitored>0</monitored>
<xferStatus>1</xferStatus>
<name>GenericDAO.cs</name>
<size>1843</size>
<created>03/31/10 11:41:10 AM</created>
<modified>03/31/10 11:41:10 AM</modified>
<tPathList><tPath>http://hwcdn.net/p2f4h2b5/cds/testing/GenericDAO.cs</tPath>
</tPathList>
<tPath>http://hwcdn.net/p2f4h2b5/cds/testing/GenericDAO.cs</tPath>
<oPathList><oPath>http://hwcdn.net/p2f4h2b5/w9m3i4q9/GenericDAO.cs</oPath>
</oPathList>
<oPath>http://hwcdn.net/p2f4h2b5/w9m3i4q9/GenericDAO.cs</oPath>
<aPath></aPath>
</file>
<nEntries>2</nEntries>
</directory>
那么有文档中的两个文件,我怎么可以递归地或迭代得到的文件,大小等..?
的反应是字符串格式,并且转换成XML如下:
XmlTextReader textReader = new XmlTextReader(hwresponse);
你问一个问题在这里?什么是“回应”? – Oded 2010-03-31 17:56:32