我有一个代码,我需要返回的值,但我认为我不能正确地将return
声明。我需要IP地址的组合列表在python返回到调用函数现在不知道如何从函数返回值
def call_me():
ACCESS_KEY= "XX"
SECRET_KEY= "XXXX"
regions = ['us-west-2','eu-central-1','ap-southeast-1']
for region in regions:
instance_information = {}
ip_dict = {}
client = boto3.client('ec2',aws_access_key_id=ACCESS_KEY,aws_secret_access_key=SECRET_KEY,region_name=region,)
addresses_dict = client.describe_addresses().get('Addresses')
for address in addresses_dict:
if address.get('InstanceId'):
instance_information[address['InstanceId']] = [address.get('PublicIp')]
# print instance_information
dex_dict = client.describe_tags().get('Tags')
for dex in dex_dict:
if instance_information.get(dex['ResourceId']):
instance_information[dex['ResourceId']].append(dex.get('Value'))
for instance in instance_information:
if len(instance_information[instance]) == 2:
ip_dict[instance_information[instance][0]] = instance_information[instance][1]
else:
ip_dict[instance_information[instance][0]] = ''
# print (json.dumps(instance_information,indent=4))
#print type(instance_information)
ip_list = [i[0] for i in instance_information.values()]
print (ip_list)
我不知道在哪里发生的,因为return ip_list
声明,这个运行在3个地区
我没有返回前2个区域的值,只有最后一个区域的IP返回 – Kittystone
看到我的更新。 –
尝试你的代码,米不能得到它的权利,有缩进问题 – Kittystone