我想将我的De序列化JSON响应中的值返回给不同的输出,但是当我去输出它们时,我只能看到RootObject属性。Deserilized Json字符串到多个输出
在SSIS脚本组件我已经创建了如下输出
我已经宣布了以下类。
public class Application
{
public int App_ID { get; set; }
public string App_Ref { get; set; }
public string Status { get; set; }
public string Error_Code { get; set; }
public string Error_Message { get; set; }
public string Create_Dt { get; set; }
public string Modify_Dt { get; set; }
public string Client_Name { get; set; }
public string Client_Code { get; set; }
public string Centrelink_Status { get; set; }
}
public class Response
{
public List<Application> Applications { get; set; }
public string Current_Dt { get; set; }
public string Last_App_Dt { get; set; }
public int Count { get; set; }
public int Total { get; set; }
}
public class RootObject
{
public bool Success { get; set; }
public Response Response { get; set; }
}
我原始的Json响应看起来像这样。
{
"Success": true,
"Response": {
"Applications": [
{
"App_ID": 1638486,
"App_Ref": "Test Example",
"Status": "Complete",
"Error_Code": null,
"Error_Message": null,
"Create_Dt": "2014-05-14 03:09:01.030 +00:00",
"Modify_Dt": "2014-05-14 03:10:59.757 +00:00",
"Client_Name": "Silver Chef",
"Client_Code": "SLVC01",
"Centrelink_Status": "Receiving_Logons"
},
{
"App_ID": 1637906,
"App_Ref": "SME Demo",
"Status": "Complete",
"Error_Code": null,
"Error_Message": null,
"Create_Dt": "2015-10-08 03:07:26.793 +00:00",
"Modify_Dt": "2015-10-08 03:23:32.833 +00:00",
"Client_Name": "Silver Chef",
"Client_Code": "SLVC01",
"Centrelink_Status": "Receiving_Logons"
},
{
"App_ID": 1585286,
"App_Ref": "Test",
"Status": "Receiving_Logons",
"Error_Code": null,
"Error_Message": null,
"Create_Dt": "2015-12-04 03:12:49.617 +00:00",
"Modify_Dt": "2015-12-04 03:12:49.617 +00:00",
"Client_Name": "Silver Chef",
"Client_Code": "SLVC01",
"Centrelink_Status": "Receiving_Logons"
},
{
"App_ID": 1585398,
"App_Ref": "Test",
"Status": "Receiving_Logons",
"Error_Code": null,
"Error_Message": null,
"Create_Dt": "2015-12-04 03:27:59.023 +00:00",
"Modify_Dt": "2015-12-04 03:27:59.023 +00:00",
"Client_Name": "Silver Chef",
"Client_Code": "SLVC01",
"Centrelink_Status": "Receiving_Logons"
},
{
"App_ID": 1585400,
"App_Ref": "Test",
"Status": "Receiving_Logons",
"Error_Code": null,
"Error_Message": null,
"Create_Dt": "2015-12-04 03:28:22.903 +00:00",
"Modify_Dt": "2015-12-04 03:28:22.903 +00:00",
"Client_Name": "Silver Chef",
"Client_Code": "SLVC01",
"Centrelink_Status": "Receiving_Logons"
}
],
"Current_Dt": "2016-11-11 01:01:01.743 +00:00",
"Last_App_Dt": "2016-10-03 22:48:56.397 +00:00",
"Count": 500,
"Total": 1870
}
}
该方法已用于发送和接收响应是这样的,它似乎是反序列化没有错误。我可以输出“成功”属性。
private RootObject GetWebServiceResult(string vAPIUrl)
{
string vAPIToken = Variables.APIToken;
//Create Web Request
HttpWebRequest apireq = (HttpWebRequest)WebRequest.Create(vAPIUrl);
apireq.ContentType = "application/json";
apireq.Method = "POST";
string jsonPostStr = "{\"Settings\": {\"API_Token\": \"" + vAPIToken + "\"}, \"Payload\": {}}";
byte[] postString = Encoding.UTF8.GetBytes(jsonPostStr);
apireq.ContentLength = postString.Length;
Stream jsonStream = apireq.GetRequestStream();
jsonStream.Write(postString, 0, postString.Length);
jsonStream.Close();
// Get Web Response
HttpWebResponse apirsp = (HttpWebResponse)apireq.GetResponse();
RootObject jsonResponse = null;
Stream jsonRspStream = apirsp.GetResponseStream();
string apiResponseString = null;
using (StreamReader reader = new StreamReader(jsonRspStream))
{
apiResponseString = reader.ReadToEnd();
Console.WriteLine(apiResponseString);
reader.Close();
}
JavaScriptSerializer returnJson = new JavaScriptSerializer();
//var serialJsonStr = returnJson.Serialize(apiResponseString);
System.Windows.Forms.MessageBox.Show(apiResponseString);
jsonResponse = returnJson.Deserialize<RootObject>(apiResponseString);
return jsonResponse;
}
但是,当我尝试写入应用程序输出缓冲区返回我只看到成功和响应。 (不能输出字符串响应,但认为这是因为它超过8000个字符)
当我尝试设置每个应用程序的值时,我看到了这一点。
我在我的foreach语句中出现以下错误。
“foreach语句无法在类型 'ScriptMain.Response' 的变量操作,因为 'ScriptMain.Response' 不包含 '的GetEnumerator' 一个 公共定义”
请帮帮忙!这让我疯狂!我究竟做错了什么?
您的'Response'对象不是列举的'List'。如果你想循环Application对象,你需要去'outPutResponse.Response.Applications'。否则一切看起来不错。 – Searching
请仅添加代码 – Rahul
Rahul的必要/相关部分,我认为我发布的所有内容都与我遇到的错误相关。 –