尝试检索数据并存储为变量时获取意外的T_STRING

Question

我无法使$ firstname等于$ row ['Firstname']。与姓氏一样。

$locationsQuery='select Firstname, Lastname, from locations where 
username=$username; 
$results = sqlsrv_query($conn, $locationsQuery, array($desiredusername)); 
while($row = sqlsrv_fetch_array($results)) 
{ 
$firstname = $row['Firstname']; 
$lastname = $row['Lastname']; 
} 

Answer 1

你缺少一个'在含$locationsQuery第一线的末端，在;