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有一种将选择结果用于同一选择的方法?如何将选择结果用于相同的选择
这样的事情?
选择10作为数字,(数字/ 2)为一半FROM表格
Ty。
编辑//////////
好球员,这是实打实的。
SELECT * FROM (SELECT
(SUM(
CASE
WHEN JVB0 = 1 AND JHIT0 = 0 AND JER0 = ' ' THEN '1'
WHEN JVB0 = 1 AND JHIT0 = 0 AND JER0 = '' THEN '1'
WHEN JVB0 = 1 AND JSF0 = 1 AND JSH0 = 1 THEN '1'
ELSE 0
END)+
SUM(CASE
WHEN JDP0 = 1 OR JDP0 = 2 THEN '2'
WHEN JDP0 = 3 OR JDP0 = 4 THEN '3'
WHEN JOR0 = 1 THEN '1'
WHEN JACTB0 != '' THEN '1'
ELSE 0
END)) as tercios_thrown,
我必须把tercios_thrown的结果和一个使用tercios_thrown作为主数字的公式。因此,我认为,它可能是其他的方式来做到这一点没有这样做:
SELECT * FROM (SELECT
(SUM(
CASE
WHEN JVB0 = 1 AND JHIT0 = 0 AND JER0 = ' ' THEN '1'
WHEN JVB0 = 1 AND JHIT0 = 0 AND JER0 = '' THEN '1'
WHEN JVB0 = 1 AND JSF0 = 1 AND JSH0 = 1 THEN '1'
ELSE 0
END)+
SUM(CASE
WHEN JDP0 = 1 OR JDP0 = 2 THEN '2'
WHEN JDP0 = 3 OR JDP0 = 4 THEN '3'
WHEN JOR0 = 1 THEN '1'
WHEN JACTB0 != '' THEN '1'
ELSE 0
END)) as tercios_thrown,
((SUM(
CASE
WHEN JVB0 = 1 AND JHIT0 = 0 AND JER0 = ' ' THEN '1'
WHEN JVB0 = 1 AND JHIT0 = 0 AND JER0 = '' THEN '1'
WHEN JVB0 = 1 AND JSF0 = 1 AND JSH0 = 1 THEN '1'
ELSE 0
END)+
SUM(CASE
WHEN JDP0 = 1 OR JDP0 = 2 THEN '2'
WHEN JDP0 = 3 OR JDP0 = 4 THEN '3'
WHEN JOR0 = 1 THEN '1'
WHEN JACTB0 != '' THEN '1'
ELSE 0
END))/3) as the_other_value
在这种情况下执行'SELECT 10,10/2',那么实际上试图实现什么呢?随着对问题的更好理解,我们可能能够找到解决方案。 :) – 2014-12-03 20:34:01
谢谢@DanJ我更新了这个问题 – jCaMaX 2014-12-03 21:36:19