我有一个maven SWT项目,有多个依赖项:依赖项1,依赖项2,依赖项3,....,依赖项n。如何使用包含依赖关系子集的maven生成可执行jar?
我想创建一个只包含项目和依赖项1和依赖项2的可执行jar,但其他依赖项将复制到/ lib目录中。
这里是我的组装配置:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.2-beta-5</version>
<dependencies>
<dependency>
<groupId>com.company</groupId>
<artifactId>dependency1</artifactId>
<version>1.0-SNAPSHOT</version>
</dependency>
<dependency>
<groupId>com.company</groupId>
<artifactId>dependency2</artifactId>
<version>1.0</version>
</dependency>
</dependencies>
<configuration>
<descriptors>
<descriptor>mvnDescript.xml</descriptor>
</descriptors>
<archive>
<manifest>
<addClasspath>true</addClasspath>
<mainClass>${project.build.mainClass}</mainClass>
</manifest>
</archive>
</configuration>
<executions>
<execution>
<id>make-my-jar-with-dependencies</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
和mvnDescript.xml:
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<formats>
<format>dir</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<dependencySets>
<dependencySet>
<outputDirectory>/</outputDirectory>
<unpack>false</unpack>
<includes>
<include>${artifact}</include>
</includes>
</dependencySet>
<dependencySet>
<outputDirectory>/lib</outputDirectory>
<unpack>false</unpack>
<excludes>
<exclude>${artifact}</exclude>
</excludes>
</dependencySet>
</dependencySets>
</assembly>
如果标记除1所有的依赖和2 “提供 ”,并使用 “ JAR-与依赖性 descriptorRef>” 它不工作? –