按日期时间字段分组

Question

我有一个包含ID字段和3个日期时间字段的表。我需要得到每个日期时间字段monthwise.I的数量正在使用

Select to_char(datatime1,'Mon-yyyy'),count(id) from table 
where datetime1 is not null 

Select to_char(datatime2,'Mon-yyyy'),count(id) from table 
where datetime2 is not null 

Select to_char(datatime3,'Mon-yyyy'),count(id) from table 
where datetime3 is not null 

然后我复制这导致到Excel和下面设置数据：

Month  CountID(datetime1) CountID(datetime2) CountID(datetime3) 
June-2013 50     20     16 
July-2013 24     10     56 

我在想，如果有一种方式我可以结合这三个查询，而不是一次写入一次查询？

Answer 1

尝试

select p , sum(cnt1) as cnt1 , sum(cnt2) as cnt1 , sum(cnt3) as cnt3 
from (select to_char(datetime1,'Mon-yyyy') as p , 
       count(id)      as cnt1 , 
       0        as cnt2 , 
       0        as cnt3 
     from table 
     where datetime1 is not null 
     group by to_char(datetime1,'Mon-yyyy') 
     UNION ALL 
     select to_char(datetime2,'Mon-yyyy') as p , 
       0        as cnt1 , 
       count(id)      as cnt2 , 
       0        as cnt3 
     from table 
     where datetime2 is not null 
     group by to_char(datetime2,'Mon-yyyy') 
     UNION ALL 
     select to_char(datetime3,'Mon-yyyy') as p , 
       0        as cnt1 , 
       0        as cnt2 , 
       count(id)      as cnt3 
     from table 
     where datetime2 is not null 
     group by to_char(datetime2,'Mon-yyyy') 
    ) t 
group by t.p 
order by t.p 

还是可以说是简单的工会+左连接：

select to_char(t.dt,'Mon-yyyy') as period , 
     sum(case when t1.id is not null then 1 else 0 end) as cnt1 , 
     sum(case when t2.id is not null then 1 else 0 end) as cnt2 , 
     sum(case when t3.id is not null then 1 else 0 end) as cnt3 
from (select datetime1 as dt from table where datetime1 is not null 
     UNION 
     select datetime2 as dt from table where datetime2 is not null 
     UNION 
     select datetime3 as dt from table where datetime3 is not null 
    ) t 
left join table t1 on t1.datetime1 = t.dt 
left join table t2 on t2.datetime2 = t.dt 
left join table t3 on t3.datetime3 = t.dt 
group by to_char(t.dt,'Mon-yyyy') 

不止一种方法去做一件事。