2
import pymongo
import sys
client=pymongo.MongoClient('localhost',27017)
db=client.rop
try:
cntcur=db.albums.aggregate([{"$unwind":"$images"},"$group":"_id":"null","count":{'$sum':1}}}])
cursor1=db.images.find()
for im in cursor1:
id1=int(im['_id'])
cnt=0
cursor= db.albums.aggregate([{"$unwind":"$images"}])
print id1
for image in cursor:
print "moving to images collection"
ig=image['images']
if (id1 == ig):
break;
else:
cnt=cnt+1
if (cnt == cntr):
print "removing"
db.images.remove({'_id':id1})
except Exception as e:
print "unexpected error", type(e),e
我在行ig=image['images']
中收到错误。我试图将其更改为ig=int(image['images'])
,但我得到同样的错误。字符串索引必须是python代码中的一个整数位置
游标是否返回'dict'对象的列表?尝试“打印图像”和“打印类型(图像)”。 – ZdaR
打印图像我得到“确定”和打印类型(图像)我得到 –
Svati
@ ZdaR是在pymongo它返回一个字典与Unicode密钥和价值 – The6thSense