如何从PHP中检索信息并在javascript中使用它

Question

我有兴趣从我的联系表单中检索用户的姓名和电子邮件，并使用它显示如下所示：“感谢您的留言$ name，我们将回复至以下邮箱：$电子邮件”我想更改中，.done功能

这里是JavaScript：

 $.ajax({ 
     type: 'POST', 
     url: "sendemail.php", 
     data: { 
      Name: $form.find("input[name='name']").val(), 
      Subject: $form.find("input[name='subject']").val(), 
      Email: $form.find("input[name='email']").val(), 
      message: $form.find("textarea[name=message]").val(), 
     }, 
     beforeSend: function() { 
      form.append(form_status.html('<p style="font-weight:bold;color:white;"><i class="fa fa-spinner w3-text-white w3-spin" style="font-size:50px"></i> Email is sending...</p>').fadeIn()); 



     } 
    }).done(function (data) { 
     //here is the function i want to insert the information 
     form_status.html('<p style="color:white;" class="text-success w3-animate-fading"><i class="fa fa-check fa-2x" aria-hidden ="true"></i>\n\ 
    Message sent. Thank you for contacting us phpName, we will reply to the following email: phpEmail <i class="fa fa-smile-o fa-2x" aria-hidden="true"></i> </p>') 
       .delay(7000).fadeOut(); 



    }); 

Answer 1

var name = $form.find("input[name='name']").val(); 
 
var email = $form.find("input[name='email']").val(); 
 

 
$.ajax({ 
 
    type: 'POST', 
 
    url: "sendemail.php", 
 
    data: { 
 
     Name: name, 
 
     Subject: $form.find("input[name='subject']").val(), 
 
     Email: email, 
 
     message: $form.find("textarea[name=message]").val(), 
 
    }, 
 
    beforeSend: function() { 
 
     form.append(form_status.html('<p style="font-weight:bold;color:white;"> < i class = "fa fa-spinner w3-text-white w3-spin" style = "font-size:50px" > < /i>Email is sending... < /p>').fadeIn()); 
 
    } 
 
}).done(function(data) { 
 
    //here is the function i want to retrieve the data from php 
 
    form_status.html('<p style="color:white;" class="text-success w3 - animate - fading "><i class="fa fa - check fa - 2 x " aria-hidden ="true "></i>\n\ 
 
      Message sent. Thank you for contacting us ' + name + ', we will reply to your email shortly. <i class="fa fa - smile - o fa - 2 x " aria-hidden="true "></i></p>') 
 
     .delay(7000).fadeOut(); 
 
});

既然你已经在表单中的名称和电子邮件信息，我不明白你为什么不使用它。你甚至不需要从服务器请求这些信息。不过，我建议在sendemail.php文件中，如果可以发送电子邮件，则返回包含状态的对象。这样，如果服务器出现问题，您可以显示错误消息。比如像这样：

{ 
 
    success: true, 
 
    message: '', 
 
    errorCode: '' 
 
}