XSLT +根据标题行的数据类型将Excel数据类型标记添加到单元格

Question

我试图使用XSLT将ss:Type="Number"分配给标题中具有数字的列中的所有数据单元格。到目前为止，我只能将它正确地分配给标题行。

XSLT：

<!-- match the Columns element and create header row --> 
<xsl:template match="Columns/*"> 
    <xsl:choose> 
     <xsl:when test="@Description[boolean(number()) or . = 0]"> 
      <ss:Cell ss:StyleID="1"> 
       <ss:Data ss:Type="Number"><xsl:apply-templates select="@Description"/></ss:Data> 
      </ss:Cell> 
      <xsl:call-template name="numberFormat"/> 
     </xsl:when> 
     <xsl:otherwise> 
      <ss:Cell ss:StyleID="1"> 
       <ss:Data ss:Type="String"><xsl:apply-templates select="@Description"/></ss:Data> 
      </ss:Cell> 
      <xsl:call-template name="stringFormat"/> 
     </xsl:otherwise> 
    </xsl:choose> 
</xsl:template> 

<xsl:template name="stringFormat" match="Row/*"> 
    <ss:Cell> 
    <ss:Data ss:Type="String"><xsl:apply-templates/></ss:Data> 
    </ss:Cell> 
</xsl:template> 

<xsl:template name="numberFormat" match="Row/*"> 
    <ss:Cell> 
    <ss:Data ss:Type="Number"><xsl:apply-templates/></ss:Data> 
    </ss:Cell> 
</xsl:template> 

结果：

 <ss:Row> 
      <ss:Cell ss:StyleID="1"> 
<ss:Data ss:Type="Number">2012001 (Number Header)</ss:Data> 
      </ss:Cell> 
      <ss:Cell ss:StyleID="1"> 
<ss:Data ss:Type="String">String Header</ss:Data> 
</ss:Cell> 
     </ss:Row> 
     <ss:Row> 
      <ss:Cell> 
<ss:Data ss:Type="Number">Row2Column1Data</ss:Data> 
      </ss:Cell> 
      <ss:Cell> 
<ss:Data ss:Type="Number">Row2Column2Data</ss:Data> 
      </ss:Cell> 
     </ss:Row> 
     <ss:Row> 
      <ss:Cell> 
<ss:Data ss:Type="Number">Row3Column1Data</ss:Data> 
      </ss:Cell> 
      <ss:Cell> 
<ss:Data ss:Type="Number">Row3Column2Data</ss:Data> 
      </ss:Cell> 
     </ss:Row> 

XML：

<Rowsets> 
<Rowset> 
    <Columns> 
     <Column Description="_2012001"/> 
     <Column Description="StringHeader"/> 
    </Columns> 
    <Row> 
     <_2012001>Row2Column1Data</_2012001> 
     <StringHeader>Row2Column2Data</StringHeader> 
    </Row> 
    <Row> 
     <_2012001>Row3Column1Data</_2012001> 
     <StringHeader>Row3Column2Data</StringHeader> 
    </Row> 
</Rowset> 
</Rowsets> 

目前，无论哪个模板是最后优先所以在这种情况下，我的“NUMBERFORMAT”模板是最后的ss:type设为即使我明确地调用模板数...

更新： 所需的输出

//First header cell contains a numeric value -- the cell should have ss:Type="Number" 
      <ss:Row> 
       <ss:Cell ss:StyleID="1"> 
    <ss:Data ss:Type="Number">_2012001 (Number Header)</ss:Data> 
       </ss:Cell> 
//Second header cell contains a string value -- the cell should have ss:Type="String" 
       <ss:Cell ss:StyleID="1"> 
    <ss:Data ss:Type="String">String Header</ss:Data> 
       </ss:Cell> 
      </ss:Row> 

//ss:Type="Number" for the first column because the header row of that column contains a number 
      <ss:Row> 
       <ss:Cell> 
    <ss:Data ss:Type="Number">Row2Column1Data</ss:Data> 
       </ss:Cell> 
//ss:Type="String" for the second column because the header row of that column is a String 
       <ss:Cell> 
    <ss:Data ss:Type="String">Row2Column2Data</ss:Data> 
       </ss:Cell> 
      </ss:Row> 
      <ss:Row> 
//ss:Type="Number" for the first column because the header row of that column contains a number 
       <ss:Cell> 
    <ss:Data ss:Type="Number">Row3Column1Data</ss:Data> 
       </ss:Cell> 
//ss:Type="String" for the second column because the header row of that column is a String 
       <ss:Cell> 
    <ss:Data ss:Type="String">Row3Column2Data</ss:Data> 
       </ss:Cell> 
      </ss:Row> 
    ...etc. 

Answer 1

这种转变：

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
xmlns:ss="some:ss" exclude-result-prefixes="ss"> 
<xsl:output omit-xml-declaration="yes" indent="yes"/> 
<xsl:strip-space elements="*"/> 

<xsl:template match="/*"> 
    <t xmlns:ss="some:ss"> 
    <xsl:apply-templates/> 
    </t> 
</xsl:template> 

<xsl:template match="Columns | Row"> 
    <ss:Row> 
    <xsl:apply-templates/> 
    </ss:Row> 
</xsl:template> 

<xsl:template priority="2" match= 
    "Column[floor(substring(@Description, 2)) 
     = 
      floor(substring(@Description, 2)) 
     ] 
    "> 
    <ss:Cell ss:StyleID="1"> 
    <ss:Data ss:Type="Number"> 
     <xsl:value-of select="@Description"/> 
    </ss:Data> 
    </ss:Cell> 
    </xsl:template> 

    <xsl:template match="Column"> 
    <ss:Cell ss:StyleID="1"> 
    <ss:Data ss:Type="String"> 
     <xsl:value-of select="@Description"/> 
    </ss:Data> 
    </ss:Cell> 
</xsl:template> 

<xsl:template priority="2" match= 
    "Row/*[floor(substring(name(), 2)) 
     = 
     floor(substring(name(), 2)) 
     ] 
    "> 
    <ss:Cell> 
    <ss:Data ss:Type="Number"> 
     <xsl:value-of select="."/> 
    </ss:Data> 
    </ss:Cell> 
</xsl:template> 

<xsl:template match="Row/*"> 
    <ss:Cell> 
    <ss:Data ss:Type="String"> 
     <xsl:value-of select="."/> 
    </ss:Data> 
    </ss:Cell> 
</xsl:template> 
</xsl:stylesheet> 

当所提供的XML文档施加：

<Rowsets> 
    <Rowset> 
     <Columns> 
      <Column Description="_2012001"/> 
      <Column Description="StringHeader"/> 
     </Columns> 
     <Row> 
      <_2012001>Row2Column1Data</_2012001> 
      <StringHeader>Row2Column2Data</StringHeader> 
     </Row> 
     <Row> 
      <_2012001>Row3Column1Data</_2012001> 
      <StringHeader>Row3Column2Data</StringHeader> 
     </Row> 
    </Rowset> 
</Rowsets> 

产生想要的，正确的结果：

<t> 
    <ss:Row xmlns:ss="some:ss"> 
     <ss:Cell ss:StyleID="1"> 
     <ss:Data ss:Type="Number">_2012001</ss:Data> 
     </ss:Cell> 
     <ss:Cell ss:StyleID="1"> 
     <ss:Data ss:Type="String">StringHeader</ss:Data> 
     </ss:Cell> 
    </ss:Row> 
    <ss:Row xmlns:ss="some:ss"> 
     <ss:Cell> 
     <ss:Data ss:Type="Number">Row2Column1Data</ss:Data> 
     </ss:Cell> 
     <ss:Cell> 
     <ss:Data ss:Type="String">Row2Column2Data</ss:Data> 
     </ss:Cell> 
    </ss:Row> 
    <ss:Row xmlns:ss="some:ss"> 
     <ss:Cell> 
     <ss:Data ss:Type="Number">Row3Column1Data</ss:Data> 
     </ss:Cell> 
     <ss:Cell> 
     <ss:Data ss:Type="String">Row3Column2Data</ss:Data> 
     </ss:Cell> 
    </ss:Row> 
</t> 

说明：

1. 正确吨模板和模式匹配。

2. 使用floor($n) = floor($n)为true()这一事实恰好在$n可转换为整数时。