我正在编写一个程序来计算两个数组的值。我在传递函数和使用数组时遇到了问题。这里是我的代码:使用数组作为函数参数
#include <stdio.h>
#include <string.h>
#include <math.h>
const int MAX_STRING = 100;
double mean(double mean_array[]){
double mean;
for (int i=0; i<=2000000; i++){
mean = mean + mean_array[i];
}
mean = mean/2000000;
return mean;
}
double stan_dev_seq(double stan_array[]){
double mean = mean(stan_array);
double a;
for (int i=0; i<=2000000; i++){
a = a + pow(stan_array[i]-mean, 2);
}
a = sqrt(a/2000000);
return a;
}
int pearson_seq(void){
double a[2000000];
double b[2000000];
double mean_a;
double mean_b;
for (int i=0; i<=2000000; i++){
a[i] = sin(i);
b[i] = sin(i+2);
}
double stan_dev_a = stan_dev_seq(a);
double stan_dev_b = stan_dev_seq(b);
return 0;
}
int main(void) {
pearson_seq();
return 0;
}
,这里是我的错误:
person_mpi.c: In function ‘stan_dev_seq’:
person_mpi.c:22:16: error: called object ‘mean’ is not a function or function pointer
double mean = mean(stan_array);
^
person_mpi.c:22:9: note: declared here
double mean = mean(stan_array);
^
我真的不知道是怎么回事,任何帮助,将不胜感激。
使用您的变量不同的名称和功能 –