我有一个关于ClientBootStrap的问题。 这是场景;Netty ClientBootstrap重新连接到另一台服务器
- Client_X想加入Server_A。
- 但Server_A以某种方式希望Client_x加入Server_B。
- 因此Server_A向Server_B发送Server_B的信息以进行重新连接
- 只要Client_X收到RECONNECTION消息,他就尝试断开与Server_A的连接并尝试连接到Server_B。 但它失败。因为一旦客户端从Server_A断开连接,他就不能再使用断开的通道。
这看起来很简单。但这里是我的执行
@Override
public void messageReceived(ChannelHandlerContext ctx, MessageEvent e)throws Exception {
if(e.getMessage() instanceof SomePacket){
....
}else if(e.getMessage() instanceof Reconnect){ //Server_A has sent a RECONNECT Message.(Redirection)
Reconnect theReconnectPacket = (Reconnect)e.getMessage();
String hostname = theReconnectPacket.getHostname();
int port = theReconnectPacket.getPort();
this.reconnectHost = hostname;
this.reconnectPort = port;
this.currentState = 1;
ctx.getChannel().disconnect(); //DISCONNECT FROM SERVER_A
}
}
@Override
public void channelDisconnected(ChannelHandlerContext ctx,ChannelStateEvent e) throws Exception {
if(this.currentState == 1){
Channel disconnectedChannel = ctx.getChannel();
if (!disconnectedChannel.isConnected()){
SocketAddress destinationAddress = new InetSocketAddress(this.reconnectHost, this.reconnectPort);
//TRYING TO RECONNECT SERVER_B
disconnectedChannel.connect(destinationAddress); //**Error Line:java.nio.channels.ClosedChannelException**
}
}
super.channelDisconnected(ctx, e);
}
正如你可以在错误线看,我得到这个异常:java.nio.channels.ClosedChannelException。我们不能在断开连接后使用相同的频道吗?一旦断开连接,是否完成?我们如何重新创建SimpleChannelHandler中的连接?
感谢进一步的评论:)
< < < < <新方法>>>>>>
确定。所以在SimpleChannledHandler中,我使用ClientBootStrap来连接不同的端口。
@Override
public void channelDisconnected(ChannelHandlerContext ctx,ChannelStateEvent e) throws Exception {
Channel disconnectedChannel = ctx.getChannel();
final ClientDataObject oldObject = ClientDataState.clientObject.get(disconnectedChannel);
if(oldObject.getClientState() == 1){
if (!disconnectedChannel.isConnected()){
SocketAddress destinationAddress = new InetSocketAddress(this.reconnectHost, this.reconnectPort);
ChannelFuture connectFuture = bootstrap.connect(destinationAddress);
connectFuture.addListener(new ChannelFutureListener() {
@Override
public void operationComplete(ChannelFuture channelFuture) throws Exception {
Channel newChannel = channelFuture.getChannel();
ClientDataObject newObject = ClientDataState.clientObject.get(newChannel);
newObject.setClientID(oldObject.getClientID());
newObject.setClientState(oldObject.getClientState());
newObject.setRoomId(oldObject.getRoomId());
newObject.setClientState(1);
ClientDataState.clientObject.set(newChannel, newObject);
Channels.write(newChannel, new Login(newObject.getClientID()));
}});
}else{
//Channled connected
}
}
super.channelDisconnected(ctx, e);
}
但我需要知道Client_X的一些信息。一旦Client_x断开连接,管道将创建另一个SimpleChannelHandler。所以我所有的信息都消失了。我尝试使用ChannelLocal来保持客户端的状态。但它与通道对象有关,也是无用的。当我连接到newChannel时,我无法再使用旧的SimpleChannelHandlers的数据。 (如clientID,roomID等)
我的观点是如何存储信息,而不受通道(会话)的影响,我想从任何通道处理程序访问数据。
处理这个问题的方法应该像这样实现ChannelPipelineFactory吗?
public class GameClientPipelineFactory implements ChannelPipelineFactory{
private static final ClientStaticHandler SHARED = new ClientStaticHandler();
private Someobject o;
public GameClientPipelineFactory(Someobject refTOSomeObject) {
super();
this.o = refToSomeObject;
}
@Override
public ChannelPipeline getPipeline() throws Exception {
// TODO Auto-generated method stub
ChannelPipeline pipeline = Channels.pipeline();
//pipeline.addLast("delimiter", new DelimiterBasedFrameDecoder(256, Delimiters.lineDelimiter()));
pipeline.addLast("decoder", new GameClientDecoder());
pipeline.addLast("encoder", new GameClientEncoder());
pipeline.addLast("shared", SHARED); //I added this line
pipeline.addLast("logicHandler", new GameClientLogicHandler(this.o));
return pipeline;
}
但是我怎么会使用这个'共享'处理程序?每当我需要一个全局对象时,我是否应该要求通过管道获取此处理程序并从“共享”处理程序获取任何对象?这不是很长的路吗?
是的,但NETTY自己创建通道。我们如何手动创建频道?我无法在API中看到。感谢您的建议艰难。 –
就像你创建第一个socket一样:ChannelFuture f = b.connect()。sync(); – Veebs
好的,我通过在创建时将引导对象传递给ChannelHandler来解决我的问题。所以只要通道处理程序断开连接,我就使用引导对象进行重新连接。谢谢Veebs。 –