不能differenciat double和int从NSDictionary

我有一个字典，有不同的数据类型值从该字典我创建数据库的插入查询现在我的问题是如果我传递double值，那么它也进入int条件，如果我写入条件up和Int条件下降。我也尝试与isKind（of :)但同样的事情发生。不能differenciat double和int从NSDictionary

这里是我的代码以为关键字

 //MARK: INSERT RECORDS 
     func insertRecord(_ dictRecord : NSDictionary, tableName : String)->Bool 
     { 

      //Example:- INSERT INTO subject(sub_color,sub_name,sub_priority)values(125.562000,'Maths','15') 

      let strStart = "INSERT INTO " + tableName 
      var column : String = "(" 
      var values : String = "(" 

      var i = 0 
      for key in dictRecord.allKeys 
      { 
       column = (column as String) + (key as! String) + ((dictRecord.allKeys.count-1 == i) ? "" : ",") 
    //   column = "\(column) \(key) \(condition)" as NSString 


       if let strValue = dictRecord.value(forKey: (key as! String)) as? String 
       { 
        values = (values as String) + "\"" + strValue + "\"" + ((dictRecord.allKeys.count-1 == i) ? "" : ",") 
    //    values = "\(values)'\(strValue)' \(condition) " as NSString 

       }else if let doubleValue = dictRecord.value(forKey: (key as! String)) as? Double 
       { 
        values = (values as String) + String (format: "%f",doubleValue) + ((dictRecord.allKeys.count-1 == i) ? "" : ",") 
    //     let strDoubleValue = String(format: "%f", doubleValue) 
    //     values = "\(values) \(strDoubleValue) \(condition) " as NSString 


       }else if let numValue = dictRecord.value(forKey: (key as! String)) as? Int 
       { 
        values = (values as String) + String (format: "%d",numValue) + ((dictRecord.allKeys.count-1 == i) ? "" : ",") 
    //    let strNumValue = String(format: "%d", numValue) 
    //    values = "\(values) \(strNumValue) \(condition) " as NSString 


       } 
       i = i + 1 
      } 
    //  column = (column as String) + ")" 
    //  values = (values as String) + ")" 
       column = "\(column))" 
       values = "\(values))" 
      let strQuery = String(format:"%@%@values%@",strStart,column,values) 
      return self.executeQuery(strQuery) 
     }

我与代码为代码

func insertRecord(_ dictRecord : NSDictionary, tableName : String)->Bool 
    { 
     //Example:- INSERT INTO subject(sub_color,sub_name,sub_priority)values(125.562000,'Maths','15') 
     let strStart = "INSERT INTO " + tableName 
     var column : String = "(" 
     var values : String = "(" 
     var i = 0 
     for key in dictRecord.allKeys 
     { 
      column = (column as String) + (key as! String) + ((dictRecord.allKeys.count-1 == i) ? "" : ",") 
      //   column = "\(column) \(key) \(condition)" as NSString 
      if let strValue = dictRecord.value(forKey: (key as! String)) as? String 
      { 
       values = (values as String) + "\"" + strValue + "\"" + ((dictRecord.allKeys.count-1 == i) ? "" : ",") 
       //    values = "\(values)'\(strValue)' \(condition) " as NSString 
      }else if dictRecord.value(forKey: (key as! String)) is Int 
      { 
       let numValue = dictRecord.value(forKey: (key as! String)) as? Int 
       values = (values as String) + String (format: "%d",numValue!) + ((dictRecord.allKeys.count-1 == i) ? "" : ",") 
       //    let strNumValue = String(format: "%d", numValue) 
       //    values = "\(values) \(strNumValue) \(condition) " as NSString 
      }else if dictRecord.value(forKey: (key as! String)) is Double 
      { 
       let doubleValue = dictRecord.value(forKey: (key as! String)) as? Double 
       values = (values as String) + String (format: "%f",doubleValue!) + ((dictRecord.allKeys.count-1 == i) ? "" : ",") 
       //     let strDoubleValue = String(format: "%f", doubleValue) 
       //     values = "\(values) \(strDoubleValue) \(condition) " as NSString 
      }else if dictRecord.value(forKey: (key as! String)) is Float 
      { 
       let floatValue = dictRecord.value(forKey: (key as! String)) as? Float 
       values = (values as String) + String (format: "%f",floatValue!) + ((dictRecord.allKeys.count-1 == i) ? "" : ",") 
       //     let strDoubleValue = String(format: "%f", doubleValue) 
       //     values = "\(values) \(strDoubleValue) \(condition) " as NSString 
      } 
      i = i + 1 
     } 
     //  column = (column as String) + ")" 
     column = "\(column))" 
     values = "\(values))" 
     let strQuery = String(format:"%@%@values%@",strStart,column,values) 
     return self.executeQuery(strQuery) 
    }

我尝试存储

{ 
"country_Lat" = "112.00"; 
"country_Long" = 112122.000; // if always store in database like 112122 
"country_Name" = London; 
"country_Status" = 1; 
"country_id" = 2; 
createddate = "12:00"; 
updateddate = "1:00"; 
}

来源

2016-12-02 chirag shah

如果你想过一个快乐的生活作为一个Swift编码器，现在停止使用NSDictionary，并使用Swift词典。它们是打字和安全的。一个人不应该像'.value（forKey：（key as！String））那样做？双'在斯威夫特。只需在正确类型的Swift数组或字典上使用下标。 – Moritz

可能相关：[是否有正确的方法来确定NSNumber是从使用Swift的Bool派生的？]（http://stackoverflow.com/questions/30215680/is-there-a-correct-way-to-determine - 即-AN-的NSNumber-IS-派生从-A-布尔-全光照）。 –

@EricAya我试着用你的建议，但结果相同 –

我避免Any类型的字典时，我可以，但如果你的钥匙是String，并使用共同的价值类型，你的代码可以大大如果按照埃里克绫的建议简化。这里是相当于insertRecord函数。

func insertRecord(_ dictionary: [String: Any], tableName: String) -> Bool { 
    let columns = dictionary.keys.joined(separator: ",") 
    let values = dictionary.values.map { "\($0)" }.joined(separator: ",") 
    return self.executeQuery("INSERT INTO \(tableName)(\(columns))values(\(values))") 
}

也许你会被强制使用，因为旧代码的约束目标C类型。然而，尽可能地接受Swift类型和编程习惯用法。

来源

2016-12-02 15:31:23

谢谢你的回答，但在代码中，我们可以做一个像你在数据库中做的插入查询我把位置的double值总是存储int，如果我写前面的双重条件，那么我的country_id变成浮动和整个数据库显示错误的值 –

不能differenciat double和int从NSDictionary

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