图了Ruby的字符串

Question

class Person 
    def initialize(name) 
     set_name(name) 
    end 
    def name 
     @first_name + ' ' + @last_name 
    end 
    private 
    def set_name(name) 
     first_name, last_name = name.split(/\s+/) 
     set_first_name(first_name) 
     set_last_name(last_name) 
    end 
    def set_first_name(name) 
     @first_name = name 
    end 
    def set_last_name(name) 
     @last_name = name 
    end 
end 
male_names = %w{George Emmanuel Bruno Connel Cletus Samuel} 
female_names = %w{Joy Stella Patience Rita Rachael Ruth Elizabeth} 
puts "Please input your two names:" 
    n = gets 
    p = Person.new(n) 
    full_name = n.scan(/\w+/) 
    names = full_name.select do |name| 
     if male_names.include?(name) 
      nn=name 
      na = "Mr "+nn 
      puts "Welcome #{na}" 
     elsif female_names.include?(name) 
      na = "Ms "+name 
      puts "Welcome #{na}" 
     else puts "name not found!\nAre you sure you exist?" 
     end 
    end 

如果我进入Connel Samuel它将打印：

欢迎康内尔先生 欢迎塞缪尔先生

我只是它想打印：

欢迎Connel Samuel先生。

Answer 1

整个Person这里的课是一个红色的鲱鱼。你在最后的印刷品中没有使用它。你刚刚使用

n.scan(/\w+/) 

并研究你从输入中得到的单词。有两个词 - Connel和Samuel，每个都会得到他们自己的迭代。因此Welcome Mr Connel Welcome Mr Samuel。

---

要解决它，你可以检查第一或第二个名字是在男/女表并打印这个人的名字：

if p.name.split.find { |name| male_names.include?(name) } 
    puts "Welcome Mr #{p.name}" 
elsif p.name.split.find { |name| female_names.include?(name) } 
    puts "Welcome Ms #{p.name}" 
else 
    puts "name not found!\nAre you sure you exist?" 
end