SQL选择每天总计数，但按日期和小时分组（每小时运行总计）

Question

我发现了类似于我想要的东西here，但它没有给出完全正确的输出，而且我正在一个愚蠢的时刻，试图想出正确的解决方案...

我们有一个AVS服务器（实时帐户验证服务，但这是无关紧要的），我想知道有多少请求今天（或任何其他日子），在每个小时。例如，假设在上午8点到9点之间发出了100个请求，并且在9点到10点之间发出了50个请求。输出应该有在8AM，和在9AM，但低于我的查询被显示的请求的数量在每一个小时来代替。

我可以看到它为什么这样做...它通过小时分组，因此它显示我在每个小时的要求，但是这不是我想要的东西，这是每小时一个运行总计。 （所以我可以每天运行它，看看请求的数量看起来像昨天这个时间，等等......并且指出这是一个缓慢还是快速的日子。）我该怎么做？

DECLARE @CurrentDate DATETIME = '14 nov 2014' 

SELECT 
    CAST(DateCreated AS DATE) [Date], 
    DATEPART(hour,DateCreated) [Hour], 
    COUNT(ID) [Requests] 
FROM Request 
WHERE 
    DateCreated >= @CurrentDate AND Request.DateCreated < DATEADD(DAY, 1, @CurrentDate) 
GROUP BY 
    CAST(DateCreated AS DATE), 
    DATEPART(hour, DateCreated) 
ORDER BY 
    CAST(DateCreated AS DATE) 

Answer 1

感谢您对所有的答案。虽然他们没有做到我想要的东西，但这是我的最后一个问题，以防它可能帮助某人。答案的问题，也可能是我的问题，结果只显示每小时的总请求数，而不是当天的最终总数。我的查询在下面给出了每小时的请求数，以及当天的最终请求数，或者当前总数，如果是当天。

DECLARE @CurrentDate DATETIME = '17 Nov 2014' 

SELECT * FROM ( 
    SELECT DISTINCT 
     CAST(DateCreated AS DATE) [Date], 
     CASE 
      WHEN LEN(CAST(DATEPART(hour,DateCreated) AS VARCHAR)) = 1 THEN '0' + CAST(DATEPART(hour,DateCreated) AS VARCHAR) 
      ELSE CAST(DATEPART(hour,DateCreated) AS VARCHAR) 
     END + ':00:00' [Time], 
     rank() OVER (ORDER BY DATEPART(hour, DateCreated))[Requests] 
    FROM Request 
    WHERE 
     DateCreated >= @CurrentDate AND DateCreated < DATEADD(DAY, 1, @CurrentDate) 
    UNION 
    SELECT 
     CAST(@CurrentDate AS DATE), 
     CONVERT(VARCHAR(8), 
       (SELECT TOP 1 DateCreated FROM Request WHERE DateCreated >= @CurrentDate AND Request.DateCreated < DATEADD(DAY, 1, @CurrentDate) ORDER BY DateCreated DESC), 
       108), 
     (SELECT COUNT(*) from Request WHERE DateCreated >= @CurrentDate AND Request.DateCreated < DATEADD(DAY, 1, @CurrentDate)) 
     ) t 
WHERE t.Requests > 0   
ORDER BY t.Time 

今天运行查询提供了这样的输出：

+------------+----------+----------+ 
| Date | Time | Requests | 
+------------+----------+----------+ 
| 2014-11-17 | 07:00:00 |  1 | 
| 2014-11-17 | 08:00:00 |  9 | 
| 2014-11-17 | 09:00:00 |  49 | 
| 2014-11-17 | 10:00:00 |  113 | 
| 2014-11-17 | 11:00:00 |  225 | 
| 2014-11-17 | 12:00:00 |  294 | 
| 2014-11-17 | 13:00:00 |  363 | 
| 2014-11-17 | 13:09:46 |  383 | 
+------------+----------+----------+ 

Answer 2

DECLARE @CurrentDate DATETIME = '14 nov 2014'; 

WITH hourValues(hourVal) as (
    select distinct cast(convert(varchar(14), @CurrentDate, 120) + '00' as datetime) 
    from [Request] 
    where datediff(day, [DateCreated], @CurrentDate) = 0) 
SELECT 
    CAST(DateCreated AS DATE) [Date], 
    hourVal, 
    COUNT(case when [DateCreated] < dateadd(hour, 1, hourVal) then 1 else null end) [Requests] 
FROM Request, hourValues 
WHERE 
    datediff(day, [DateCreated], @CurrentDate) = 0 
GROUP BY 
    CAST(DateCreated AS DATE), 
    hourVal 
ORDER BY 
    [Date], 
    HourVal 

Answer 3

下面应该工作

DECLARE @CurrentDate DATETIME = '13 nov 2014' 

SELECT DISTINCT 
    CAST(DateCreated AS DATE) [Date], 
    DATEPART(hour,DateCreated) [Hour], 
    COUNT(ID) OVER (ORDER BY DATEPART(hour, DateCreated)) 
FROM Request 
WHERE 
    DateCreated >= @CurrentDate AND DateCreated < DATEADD(DAY, 1, @CurrentDate) 
ORDER BY 
    DATEPART(hour, DateCreated) 

Answer 4

 --if you use MS SQL Server 2008 R2 or later version (2012/2014) then try this 

DECLARE @CurrentDate DATE = CONVERT(DATE, GETDATE() - 1) , --yesterday 
    @FinishDate AS DATE = CONVERT(DATE, GETDATE() + 1) --tomorrow 

SELECT DISTINCT 
     CONVERT(DATE, DateCreated) AS [Date] , 
     DATEPART(HOUR, DateCreated) AS [Hour] , 
     COUNT(ID) OVER (PARTITION BY CONVERT(DATE, DateCreated) ORDER BY DATEPART(HOUR, 
                   DateCreated)) AS [Cumulative Count] 
FROM Request 
WHERE CONVERT(DATE, DateCreated) BETWEEN @CurrentDate 
            AND  @FinishDate 
ORDER BY CONVERT(DATE, DateCreated) , 
     DATEPART(HOUR, DateCreated)