如何确定以Java创建文件时允许的最大路径长度

如何确定以Java创建文件时允许的最大路径长度。我正在使用Java 7，因此可以使用Java NIO2，如果有帮助，但我如何确定文件在文件系统上允许的最大长度，并确保我不尝试创建具有此类无效路径的文件。如何确定以Java创建文件时允许的最大路径长度

我想在缩短路径（子串）之前，尝试创建它之后不处理问题，特别是因为异常/错误消息可能因文件系统而异。

我不想硬编码每个平台的长度，这不会工作，因为Windows应用程序可以访问OSX filessystem ectera。

它不但不能当试图创建文件即

try 
     { 

      Path p = Paths.get("C:/User/Mesh/kkkkkkkkkkkkkkkkkkkkkkkkkkrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk.txt"); 
      Files.createFile(p); 
     } 
     catch(Exception e) 
     { 
      e.printStackTrace(); 
     }

给

java.nio.file.FileSystemException: C:\User\Mesh\kkkkkkkkkkkkkkkkkkkkkkkkkkrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk.txt: The filename, directory name, or volume label syntax is incorrect. 

    at sun.nio.fs.WindowsException.translateToIOException(WindowsException.java:86) 
    at sun.nio.fs.WindowsException.rethrowAsIOException(WindowsException.java:97) 
    at sun.nio.fs.WindowsException.rethrowAsIOException(WindowsException.java:102) 
    at sun.nio.fs.WindowsFileSystemProvider.newByteChannel(WindowsFileSystemProvider.java:229) 
    at java.nio.file.Files.newByteChannel(Files.java:315) 
    at java.nio.file.Files.createFile(Files.java:586)

比较Java 6的方法

try 
     { 
      //File file = new File("C:/User/Mesh/kkkkkkkkkkkkkkkkkkkkkkkkkkrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk.txt"); 
      Path p = Paths.get("C:/User/Mesh/kkkkkkkkkkkkkkkkkkkkkkkkkkrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk.txt"); 
      p.toFile().createNewFile(); 
      //boolean result=file.isFile(); 
      //System.out.println("Result is:"+result); 
     } 
     catch(Exception e) 
     { 
      e.printStackTrace(); 
     }

给人完全不同的错误

java.io.IOException: The filename, directory name, or volume label syntax is incorrect 
    at java.io.WinNTFileSystem.createFileExclusively(Native Method) 
    at java.io.File.createNewFile(File.java:947)

但irrelvant真的是因为我想要做的事情是创建文件前

编辑：貌似255个字符是一个很好的默认http://en.wikipedia.org/wiki/Filename反正

来源

2013-01-23 Paul Taylor

如何将它需要的是帮助，任何系统不只是我自己的 –

有一点要谨记的工作是Eclipse的，如果你正在使用的，有它自己的（相当严重），路径长度的限制。 –

我不能亲自找到实现此值的方法。在尝试打开文件并在那里处理文件时，最好简单地捕捉异常。 –

在java.nio.file.FileSystem中有一种方法getPath，可用于创建有效的路径名称，否则会引发InvalidPathException。也许这可以帮助你。

来源

2013-01-23 17:04:13 Ingo

谢谢，看起来很有用，但我认为现在我只是要编码为255个字符 –

尝试沿着这些路线的东西：

boolean success = true; 
File testFile = new File("https://stackoverflow.com/a/really/long/name"); 
try { 
    success = testFile.createNewFile(); 
} catch (IOException ioe) { 
    // anyway check the exception, the problem could have been other 
    // for example: duplicate name, lack of permissions, etc. 
    success = false; 
} 

if (!success) { 
    // error creating file 
}

来源

2013-01-23 17:02:26

我想要的是在创建文件之前检查文件名是否有效。 –

@PaulTaylor我不认为这是可以做到的。最简单的方法是尝试创建它，并在出现错误时处理它，如上所示 –

如何确定以Java创建文件时允许的最大路径长度

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