2011-10-27 92 views
1

$ delete_commant = l(t('X'),$ url,array('attributes'=> array('onclick'=>'return call_ajax(123)')));drupal call ajax function

,当我把在call_ajax函数定义警报,它警告,所以我继续写的AJAX POST方法,但是当我点击链接页面得到刷新,

如何在Drupal

实现Ajax
function call_ajax(str){alert(str); 
    var url = "post.php"; 
    var params = "lorem=ipsum&name=binny"; 
    http.open("POST", url, true); 

    //Send the proper header information along with the request 
    http.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); 
    http.setRequestHeader("Content-length", params.length); 
    http.setRequestHeader("Connection", "close"); 

    http.onreadystatechange = function() {//Call a function when the state changes. 
     if(http.readyState == 4 && http.status == 200) { 
      alert(http.responseText); 
     } 
    } 
    http.send(params); 
    } 
+0

我认为你不是初始化var http。 –

+0

atleast它应该显示错误知道,但是当我点击X,它只是刷新页 –

+0

你尝试初始化在这个例子中看起来他们正在初始化var xmlhttp; http://www.w3schools.com/ajax/ajax_aspphp .asp –

回答