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我'找一个查询来获取从我的函数的两个participant_id paramters会话ID:查找具有相同的值排从两个ID
PHP函数来获取conversation_id
public function findByUsers($user1,$user2)
MySQL表participant_conversation
+--------------+-------------------------+
|participant_id| participant_conversation|
+--------------+-------------------------+
|42360 |1 |
+--------------+-------------------------+
|42362 |5 |
+--------------+-------------------------+
|42363 |1 |
+--------------+-------------------------+
感谢您的帮助
编辑:我FO UND解决
SELECT DISTINCT (participant_conversation)
FROM users_conversations_participants
WHERE participant_id IN (42360, 42361)
GROUP BY participant_id
LIMIT 0 , 30
感谢您的帮助! 我找到了解决方案:) – Splithead 2015-04-05 21:48:04