2014-04-19 204 views
0

我是CakePHP的新手,对于如何设置模型关联有点麻烦。CakePHP的模型关联

说我有3个表:支付,预订和reservation_details数据如下

table reservations 
id | confirmation_number | guest_id 
1   123      1 

table reservation_details -a reservation can have multiple entries (multiple rooms) 
id | reservation_id | date  | time | room_id | rate 
2   1   2014-18-04 13:00  1   9.99 
3   1   2014-18-04 13:00  2   4.99 

table payments - many payments for one reservation can be made 
id | reservation_id | payment_amount | payment_type | guest_id 
4   1     14.98    Cash    1 

这里是我的模型协会

//Reservation model 
public $hasMany = array('ReservationDetail', 'Payment'); 

//ReservationDetail model 
public $belongsTo = array('Reservation'); 

//Payment model 
public $belongsTo = array('Reservation'); 
public $hasMany = array('ReservationDetail' => array('foreignKey' => 'reservation_id')); 

我想要做的是能搜索对于付款,它将返回该付款的相应预订和reservation_details。因此,它会从共享相同reservation_id的reservation_details中获取任何记录。此时预订已退回,但预订详细信息已返回空

以下搜索将从预付款和预订中返回信息,但是会返回reservation_details中的空数组。

$payment = $this->Payment->find('all',array(
             'conditions' => array(
             'Payment.guest_id' => '1' 
             ) 
           )); 

我几乎可以肯定它的加入对payments.id = payments.reservation_id的reservation_details表,而不是payments.reservation_id = reservation_details.reservation_id。当我手动将payments.id更改为1(reservation_id值)时,将返回reservation_details。

我相信,我想实现将像

SELECT reservations.*, reservation_details.*, payments.* from payments 
INNER JOIN reservations on reservations.id = payments.reservation_id 
INNER JOIN reservation_details on reservation_details.reservation_id = payments.reservation_ID 
WHERE payments.guest_id = '1' 

回答

0

Payment.php

的MySQL查询

加中可容纳的行为原样

public $actsAs = array('Containable'); 

PaymentsController.php

$payments = $this->Payment->find('all', array(
              'conditions' => array(
               'Payment.guest_id' => '1' 
              ), 
              'contain' => array(
               'Reservation' => array(
                'ReservationDetail' 
               ) 
              ) 

)); 

debug($payments); 
+0

非常感谢!完美的作品! – user3476345