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我有一个名为SkipList
的模板类和一个名为Iterator
的嵌套类。类模板中没有成员函数声明
SkipList
遵循以下定义:
template <typename Key_T, typename Mapped_T, size_t MaxLevel = 5>
class SkipList
{
typedef std::pair<Key_T, Mapped_T> ValueType;
public:
class Iterator
{
Iterator (const Iterator &);
Iterator &operator=(const Iterator &);
Iterator &operator++();
Iterator operator++(int);
Iterator &operator--();
Iterator operator--(int);
private:
//some members
};
Iterator
有一个拷贝构造函数,我的定义是这样后声明它的类外:
template <typename Key_T, typename Mapped_T,size_t MaxLevel>
SkipList<Key_T,Mapped_T,MaxLevel>::Iterator(const SkipList<Key_T,Mapped_T,MaxLevel>::Iterator &that)
但我得到以下错误:
SkipList.cpp:134:100: error: ISO C++ forbids declaration of ‘Iterator’ with no type [-fpermissive]
SkipList.cpp:134:100: error: no ‘int SkipList<Key_T, Mapped_T, MaxLevel>::Iterator(const SkipList<Key_T, Mapped_T, MaxLevel>::Iterator&)’ member function declared in class ‘SkipList<Key_T, Mapped_T, MaxLevel>’
出了什么问题?
[SSCCE](http://sscce.org)怎么样? – 2013-04-20 00:03:28
@AndyProwl我改变了这个问题 – footy 2013-04-20 00:06:00