-2
这是整个项目，它应该尽我所能地看到，但我希望在这里张贴它可以让我看到我错过的东西，我有一个温和的与Java经验量Java代码将不会打印出答案或正确读取int
package com.company;
import java.util.Random;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
// write your code here
Scanner input = new Scanner(System.in);
int number1;
int number2;
int answer;
String operator;
此计算出的数字和运营商的用户想要什么
System.out.println("Please Enter your first number");
number1 = input.nextInt();
System.out.println("Please enter your second number");
number2 = input.nextInt();
System.out.println("Please enter your operator: + , - , * ,/");
operator = input.next();
if语句应该确定用户希望其子及applys两个数字，然后调用randomEquation方法使其成为错误答案
if (operator == "+") {
answer = number1 + number2;
System.out.println("Your answer is: " + randomEquation(answer));
} else if (operator == "-") {
answer = number1 - number2;
System.out.println("Your answer is: " + randomEquation(answer));
} else if (operator == "*") {
answer = number1 * number2;
System.out.println("Your answer is: " + randomEquation(answer));
} else if (operator == "/") {
answer = number1/number2;
System.out.println("Your answer is: " + randomEquation(answer));
}
}
这种方法适用于随机其中的一个答案创建错误的答案
public static int randomEquation(int number) {
Random rand = new Random();
int random = rand.nextInt(100) + 1;
int answer = number;
if (random <= 100 && random >= 81) {
answer = number * 25;
return answer;
}
else if(random <= 80 && random >= 61){
answer += 13;
return answer;
}
else if(random <= 60 && random >= 41){
answer /= 2;
return answer;
}
else if(random <= 40 && random >= 21){
answer -= 16;
return answer;
}
else{
answer %= 4;
return answer;
}
}
}