为什么我看不到我的网站，并获得HTTP状态404？

Question

我在做使用spring mvc的servlet，我看不到我的网站。我在下面发布了我的web.xml，mvc-dispatcher-servlet.xml和控制器类。一切似乎都很好，但是当我输入“localhost：8080”时，我得到了404 http status The requested resource is not available。我错过了什么？

的web.xml：

<web-app version="2.4" 
     xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> 

    <display-name>Weather</display-name> 
    <servlet> 
     <servlet-name>mvc-dispatcher</servlet-name> 
     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 
    <servlet-mapping> 
     <servlet-name>mvc-dispatcher</servlet-name> 
     <url-pattern>/</url-pattern> 
    </servlet-mapping> 
</web-app> 

MVC-调度-servlet.xml中：

<context:component-scan base-package="com.springapp.mvc"/> 

<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
    <property name="prefix" value="/WEB-INF/pages/"/> 
    <property name="suffix" value=".jsp"/> 
</bean> 

<jpa:repositories base-package="com.springapp.mvc"/> 

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean"> 
    <property name="persistenceUnitName" value="defaultPersistenceUnit"/> 
</bean> 

<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> 
    <property name="entityManagerFactory" ref="entityManagerFactory" /> 
</bean> 

<tx:annotation-driven transaction-manager="transactionManager"/> 
<mvc:annotation-driven /> 

控制器类：

@Controller 
public class HomeController 
{ 
    Weather weather; 

    @RequestMapping(value = "/", method = RequestMethod.GET) 
    public String infoWeather(ModelMap model, HttpServletRequest req) { 

     if (!model.containsAttribute("location") && !model.containsAttribute("weather")) { 
      Language.getInstance().setLanguage(LanguageManager.getLanguage(new Locale(System.getProperty("user.language")))); 
      Location location = LocationManager.getLocation(req); 
      model.addAttribute("location", location); 
      weather = WeatherManager.getWeather(location); 
      model.addAttribute("weather", weather); 
     } 

     if (!model.containsAttribute("destination")) 
      model.addAttribute("destination", new Destination()); 

     return "index"; 
    } 

    @RequestMapping(value = "/search", method = RequestMethod.POST) 
    public String findDestination(@ModelAttribute("destination") Destination destination, BindingResult result, RedirectAttributes redirectAttrs) { 
     destination = DestinationManager.getDestination(destination.getAddress()); 
     weather = WeatherManager.getWeather(destination); 
     redirectAttrs.addFlashAttribute("weather", weather); 
     return "redirect:/"; 
    } 
} 

Answer 1

我见下文点在这里，这需要待修：

1. 一旦你部署在tomcat的webapp目录下你的应用程序中，URL应该像http://localhost:8080/<web-app-name>/<your servlet>

2. 或者你可以添加一个欢迎页面，并检查其是否工作。为此，您需要在web-xml中添加欢迎页面设置。有关线索，请参见This post。

如果不工作，请与您的战争部署共享你的tomcat目录树;和战争文件目录结构

注意：您应该能够使用zip实用程序扩展您的战争。