查找单词的文字，PHP

Question

如何解决此问题：

编写查找文本的字一个PHP程序。 后缀通过管道与文本分开。 例如：后缀| SOME_TEXT;

input：text | lorem ips llfaa Loremipsumtext。 输出：Loremipsumtext

我的代码是这样的，但逻辑也许是错误的：

$mystring = fgets(STDIN); 
$find = explode('|', $mystring); 
$pos = strpos($find, $mystring); 

if ($pos === false) { 
    echo "The string '$find' was not found in the string '$mystring'."; 
} 
else { 
    echo "The string '$find' was found in the string '$mystring',"; 
    echo " and exists at position $pos."; 
} 

Answer 1

explode()返回一个数组，所以你需要使用$find[0]为后缀，$find[1]的文本。所以它应该是：

$suffix = $find[0]; 
$text = $find[1]; 
$pos = strpos($text, $suffix); 

if ($pos === false) { 
    echo "The string '$suffix' was not found in '$text'."; 
} else { 
    echo "The string '$suffix' was found in '$text', "; 
    echo " and exists at position $pos."; 
} 

但是，这将返回后缀的位置，而不是包含它的单词。它也不检查后缀是否在单词的末尾，它会在单词的任何位置找到它。如果你想匹配单词而不仅仅是字符串，正则表达式会是一个更好的方法。

$suffix = $find[0]; 
$regexp = '/\b[a-z]*' . $suffix . '\b/i'; 
$text = $find[1]; 
$found = preg_match($regexp, $text, $match); 

if ($found) { 
    echo echo "The suffix '$suffix' was found in '$text', "; 
    echo " and exists in the word '$match[0]'."; 
} else { 
    echo "The suffix '$suffix' was not found in '$text'."; 
}