getJSONObject与数组

Question

我正在尝试使用android和php json，我尝试获取像这样的东西，它是如何在示例中显示的。示例json respone是：{“android”：[{“ver”：“1.5”，“name”：“Cupcake”，“api”：“API level 3”}，{“ver”：“ 1.6“，”name“：”Donut“，”api“：”API level 4“}]}

and my json respone is： [{”post_id“：”3“，”user_id“：”1 “ ”post_inhalt“： ”罗立“， ”喜欢“： ”1“}，{ ”POST_ID“： ”4“， ”USER_ID“： ”1“， ”post_inhalt“： ”拉拉“， ”喜欢“：” 2 “}]

ther是我的问题，我想要一个数组的对象;

我的php代码看起来像这样。

<?php 
$con=mysqli_connect("localhost","root","","my_db"); 
//echo "Welcome, I am connecting Android to PHP, MySQL"; 

if (mysqli_connect_errno($con)) 
{ 
    //echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
} 

$user_id = "1"; 
//Für die Überprüfung 
$result = mysqli_query($con, "SELECT * FROM post where user_id='$user_id'"); 

$response = array(); 

// fetch data in array format 
while ($row = mysqli_fetch_array($result, MYSQL_ASSOC)) { 

    //$response["code"] = 1; 
    // Fetch data of Fname Column and store in array of row_array 
    /* 
    $row_array["post"]['post_id'] = $row['post_id']; 
    $row_array["post"]['user_id'] = $row['user_id']; 
    $row_array["post"]['post_inhalt'] = $row['post_inhalt']; 
    $row_array["post"]['likes'] = $row['likes']; 
    */ 

    $row_array['post_id'] = $row['post_id']; 
    $row_array['user_id'] = $row['user_id']; 
    $row_array['post_inhalt'] = $row['post_inhalt']; 
    $row_array['likes'] = $row['likes']; 


    //push the values in the array 
    array_push($response,$row_array); 

    } 


print json_encode($response); 



mysqli_close($con); 
?> 

我希望把这个在我的Android列表视图，但每次我跑我的应用程序，错误： “org.json.JSONArray org.json.JSONObject.getJSONArray（java.lang.String中）”在空对象参考

因为我认为数据不能从我的android找到。我不是最好的机器人，所以也许有人可以帮助我。

这里是我的我的PHP代码更新：

//while ($row = mysqli_fetch_array($result, MYSQL_ASSOC)) { 
if(mysqli_num_rows($result) > 0) { 



    $row = mysqli_fetch_array($result); 
    //$response["code"] = 1; 
    // Fetch data of Fname Column and store in array of row_array 

    /* 
    $row_array["post"]['post_id'] = $row['post_id']; 
    $row_array["post"]['user_id'] = $row['user_id']; 
    $row_array["post"]['post_inhalt'] = $row['post_inhalt']; 
    $row_array["post"]['likes'] = $row['likes']; 
    */ 
    //$row_array = array(); 

    $row_array['post_id'] = $row['post_id']; 
    $row_array['user_id'] = $row['user_id']; 
    $row_array['post_inhalt'] = $row['post_inhalt']; 
    $row_array['likes'] = $row['likes']; 

    //Funktioniert auch, gib aber nur ein array zurück 
    //$response[] = $row; 

    $response["post"] = array(); 
    //push the values in the array 
    array_push($response["post"],$row_array); 

} 


print json_encode($response); 

Answer 1

行阵列添加到您的resporse这样的：

$respone["android"][$i] = $row_array;

ofcouse $i是阵列中的地方

类似这样的：

$response["android"] = array(); 
$i = 0; 
while ($row = mysqli_fetch_array($result, MYSQL_ASSOC)) { 

    $row_array['post_id'] = $row['post_id']; 
    $row_array['user_id'] = $row['user_id']; 
    $row_array['post_inhalt'] = $row['post_inhalt']; 
    $row_array['likes'] = $row['likes']; 

    $response["android"][$i] = $row_array; 
}