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这是我的功能代码,获得和功能
function icerikduzenle($a,$b,$c)
{
global $veriyolu;
$menuid=$c;
$icerik=$b;
$icerik_id=$a;
$guncelle=mysql_query("update icerik set icerik='$icerik' , menu_id='$menu_id' where icerik_id='$icerik_id'",$veriyolu);
if($guncelle){
echo "<script>alert(' İçerik düzenlendi! ')</script>";
echo "<meta http-equiv='Refresh' content='0; URL=yonetim.php?menu=2'>";
}else{
echo "<script>alert(' !! İçerik düzenlenemedi !! ')</script>";
echo "<meta http-equiv='Refresh' content='0; URL=yonetim.php?menu=2'>";
}
}
我觉得我有问题_POST瓦尔。清单DATAS没有错误,但没有更新DATAS
这是主代码 我不喜欢的连接表中的mysql我用了2 sql语句 我想POST变量不要去任何地方
$iceriksql="select * from icerik order by menu_id asc";
$iceriksorgu= mysql_query($iceriksql);
echo "<table>";
while($iceriksonuc=mysql_fetch_array($iceriksorgu))
{
echo "<form method='post' action='yonetim.php?menu=2&icerikid={$iceriksonuc["icerik_id"]}&git=icerikduzenle'>";
$menusql= "select * from menu order by menu_id asc";
$menusorgu = mysql_query($menusql);
echo "<tr><td><select name='menu_id'>";
while ($menusonuc=mysql_fetch_array($menusorgu))
{
if ($menusonuc['menu_id']==$iceriksonuc['menu_id'])
{
echo "<option value='{$menusonuc["menu_id"]}' selected>{$menusonuc["menu"]}</option>";
}
else
{
echo "<option value='{$menusonuc["menu_id"]}'>{$menusonuc["menu"]}</option>";
}
}
echo "</select></td>";
echo "<td><textarea name='icerik'>{$iceriksonuc["icerik"]}</textarea></td><td><input type='submit' name='submit' value='Düzenle' /></td></tr>";
echo "</form>";
}
echo "</table>";
这是最后一部分我的代码
switch ($_GET['git']){
case "icerikduzenle";
icerikduzenle($_REQUEST['icerik_id'],$_REQUEST['icerik'],$_REQUEST['menu_id']);
break;
}
你能在这里回显查询吗? – Sahal
这种情况是错误的... – jpganz18
变量'$ veriyolu'是你的资源标识符,它对于那个函数是全局的吗? – Sahal