我在做什么看起来像一个简单的查询基本上是做对competition_id一个WHERE子句和prize_type的Yii - CDbCriteria意想不到的效果
$criteria = new CDbCriteria;
$criteria->select = 't.*, myuser.firstname, myuser.surname';
$criteria->join ='LEFT JOIN myuser ON myuser.user_id = t.user_id';
$criteria->condition = 't.competition_id = :competition_id';
$criteria->condition = 't.prize_type = :prize_type';
$criteria->params = array(":competition_id" => $competition_id);
$criteria->params = array(":prize_type" => "1");
$winners = CompetitionWinners::model()->findAll($criteria);
任何人都可以提出什么是错我的代码...我期待大约4行..但是超过600?
我只想做...
WHERE competition_id = 123 AND prize_type = 1;
有一个简单的功能,简单地输出的SQL查询这个单一CDbCriteria“事件”?
http://stackoverflow.com/questions/10629728/yii-how-to-print-sql-used-by- findall和http://stackoverflow.com/questions/4435886/yii-model-to-array/4577768#4577768可以帮助你调试查询 – Pentium10
任何人都可以解释为什么这将是downvoted - 答案被接受后一天?它确实在某种程度上破坏了社区,并没有给出任何理由。 – Zabs