这里是绝对初学者(FIRST POST),我刚刚完成了一项任务,我必须创建一个程序,让用户创建员工工资单,然后显示他们搜索姓氏,姓氏,雇员号码等用户输入接受是否在C++中输入大写字母或小写字母
我有一个问题,如果我创建一个记录南希戴维森例如如果我正确搜索Nancy或Davidson,我可以正确输出这条记录。如果我搜索南希或戴维森它不会找到它。
我正在使用结构来存储每个员工的详细信息,将它们写入数据文件,然后读取该文件以显示记录。
即使我搜索NAncY,有没有一种方法可以让记录仍然显示?
这是我为我的搜索按姓氏功能代码:
//Record search by employee SURNAME only
void searchSurname(Employee data[], int row)
{
string surname, again;
double wholeTot=0, wholeNet=0;
again = "y";
while (again=="y"||again=="Y")
{
row=0;
bool found = false;
clrscr();
cout << "Please enter Employee SURNAME : ";
Input(surname);
clrscr();
cout << "Surname Search results for " << surname << ". \n\n\n";
readFile (data, row);
int stop=row;
for (row = 0; row < (stop) ; row++)
if (surname == data[row].surname)
{
deconvertDate(data[row].date);
cout << " ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~" << endl
<< " # Employee Number - " << RIGHT(19,2) << data[row].empnum << " #" << endl
<< " # Employee Surname - " << RIGHT(18,2) << data[row].surname << " #" << endl
<< " # Employee Forename - " << RIGHT(17,2) << data[row].forename << " #" << endl
<< " # Department Number - " << RIGHT(17,2) << data[row].dept << " #" << endl
<< " # Normal Hours Worked - " << RIGHT(15,2) << data[row].hours << " #" << endl
<< " # Overtime Hours Worked - " << RIGHT(13,2) << data[row].ohours << " #" << endl
<< " # Pay Rate - " << RIGHT(26,2) << data[row].rate << " #" << endl
<< " # Gross Pay - " << RIGHT(25,2) << data[row].grosspay << " #" << endl
<< " # Tax - " << RIGHT(31,2) << data[row].tax << " #" << endl
<< " # National Insurance - " << RIGHT(16,2) << data[row].natin << " #" << endl
<< " # Total Deductions - " << RIGHT(18,2) << data[row].totalDeduct << " #" << endl
<< " # Net Pay - " << RIGHT(27,2) << data[row].net << " #" << endl
<< " # Week Ending - " << RIGHT(23,2) << data[row].date << " #" << endl
<< " ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~" << endl << endl << endl;
wholeTot+=data[row].grosspay;
wholeNet+=data[row].net;
cout << "The total recorded GROSS PAY of " << data[row].surname << " is :" << wholeTot << endl;
cout << " and the total recorded NET PAY is :" << wholeNet << endl << endl;
found = true;
}
else
if (found = false)
{
cout << "No results found for that SURNAME!" << endl;
}
的
std::ctype
方面如果你能提供一个显示问题并编译它将使我们能够更好地帮助你的代码的一小部分。简单的答案是在比较时进行小写大小写转换,但没有代码我们不能提供更多。 – 2013-05-08 13:56:49当你存储它们时,大写所有的名字。在搜索前大写搜索输入。而已。 – stardust 2013-05-08 13:56:55
最好的方法是在比较时将您正在比较的文本转换为大写或小写(=>按照您的希望存储和抽取它们,但是将它们全部以小写或大写形式进行比较) – 2013-05-08 13:57:25