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让说,我有一个包含该数据学生信息系统级分配矢量搜索
First Name Last Name ID Tuition GPA
Alex Robinson 02341 1400.50 3.45
John Brown 043261 1200.00 3.21
Rachel VanGorp 77239 600.00 4.00
James Smith 89167 1150.55 1.45
Juan Garcia 23165 1200.00 3.33
Lindsey McDonald 32501 1340.50 2.25
Tom Barry 78442 500.00 3.85
Gwen Poss 30029 1150.50 3.85
Janice Jones 44560 2200.50 2.45
Jack Price 99314 1850.55 3.12
一个文本文件,我导入项目名单为载体,这里是我的学生类和我classOfStudents类。帮助这个信息将是伟大的。我迷路了,不知道该去哪里。只有参考和一个正确的方向点将是伟大的!
class student
{
public:
student()
{
firstName = "";
lastName = "";
ID = "";
tuitionBalance = 0.0;
GPA = 0.0;
}
student(string first, string last, string id, double tuition, double gpa)
{
first = firstName;
last = lastName;
id = ID;
tuition = tuitionBalance;
gpa = GPA;
}
void openIF()
{
inFile.open("students.txt");
}
void setFirstName()
{
inFile >> temp;
firstName = temp;
}
void setLastName()
{
inFile >> temp;
lastName = temp;
}
void setID()
{
inFile >> temp;
ID = temp;
}
void setBalance()
{
inFile >> tuitionBalance;
}
void setGPA()
{
inFile >> GPA;
}
void closeIF()
{
inFile.close();
}
string firstName, lastName, ID;
double tuitionBalance, GPA;
private:
ifstream inFile;
char temp[128];
}
class classOfStudents
{
public:
vector<student> students;
classOfStudents()
{
student Students = student(firstName, lastName, ID, tuitionBalance, GPA);
students.push_back(Students);
}
void findStudent()
{
int searchID;
cout << "Enter ID of student" << endl;
cin >> searchID;
find(students.begin(), students.end(), searchID);
}
private:
string firstName, lastName, ID;
double tuitionBalance, GPA;
}
我怎么会拉与学生的只是ID
其余的信息?
你可以用'ID'作为键和'student'作为'map'作为值。 – CoryKramer
最基本的解决方案是迭代矢量,直到找到具有正确ID的“学生”;网络方法用于开始使用更复杂的数据结构(一点点)。 – SJuan76
@Cyber当我试图映射它时Visual Studio告诉我,我在地图 – user3658110