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我是android编程的初学者。我尝试使用下面的代码播出Wi-Fi直连的消息:用android直播在android中广播
公共类FileTransferService扩展IntentService {
public static final String host= "255.255.255.255";
InetAddress broadcastAddress = InetAddress.getByName(host);// Exception: Unknown host exception
int port = 8888;
protected void onHandleIntent(Intent intent) {
Log.d(WiFiDirectActivity.TAG,"m in 1");
Context context = getApplicationContext();
DatagramSocket socket;
try {
socket = new DatagramSocket(port);
socket.setBroadcast(true);
socket.connect(broadcastAddress, port);
String message = "Hello";
byte[] buffer = message.getBytes();
DatagramPacket packet = new DatagramPacket(
buffer, buffer.length, broadcastAddress, port);
socket.send(packet); // <----- Causes a SocketException
} catch (IOException e) {
Log.d(WiFiDirectActivity.TAG, e.getMessage(), e);
}
}
}
它显示我的GetByName方法()方法未知的主机异常。反正有替代方法吗?我正走在一条正确的道路上吗?我是否需要添加任何内容以发送消息。
在此先感谢
原谅我@ user2645907但Android的API正在使用? Android 4.x?或以下? – gumuruh