假设您有一个像常用于组织瓷砖地图的二维数组,则1表示实体拼块。将二维数组转换为多边形点
var map = [
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[0,0,0,0,1,1,1,1,1,1,0,0,0,0,0],
[0,0,0,0,1,1,1,1,1,1,0,0,0,0,0],
[0,0,0,0,1,1,1,1,1,1,0,0,0,0,0],
[0,0,0,0,1,1,1,1,1,1,0,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,1,0,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0,1,0,0,0],
[0,0,0,0,0,0,0,0,0,0,0,0,1,0,0],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
];
而不是正方形瓷砖,我想将此形状转换为多边形的点。阵列中的每个1都有一个像瓷砖贴图一样的宽度和高度,但我只想要将角形点重新创建为实心多边形。当1的角度与阵列中的对角线相似时,我也想要对角斜坡而不是阶梯状效果。我玩过并搜索了一个答案,但我无法弄清楚这样做的最佳方式,有什么想法?
谢谢。
谷歌'踏着squares' – nullpotent