sqHow如何根据两个日期获得每周总和值？

Question

我的表值一样......

Date Amt Cash Money Name 
15-Jun 100 10 20 GUL 
16-Jun 200 20 40 ABC 
20-Jun 300 30 60 GUL 
25-Jun 400 40 80 BCA 
28-Jun 500 50 10 GUL 
3-Jul 600 60 120 ABC 
19-Jun 700 70 140 BCA 
26-Jun 800 80 160 ABC 
7-Jul 900 90 180 GUL 
9-Jul 1000 100 200 ABC 

我需要在Oracle。我的两个日期之间的返回值的每周基总和预期的输出。

Date   Amt Cash Mony 
13 to 19 June 1000 100 200 
20 to 26 June 1500 150 300 
27 to3 July  1100 110 130 
4 to 10 July 1900 190 380 

Answer 1

下面的查询在第一个分解子查询中有输入日期（从和到）。这些可以被制作成绑定变量，或者你想用来将这些输入传递给查询的任何机制。然后我在第二个分解子查询中有测试数据;你最终的解决方案中并不需要这些。我在“周”因子查询中创建了所有需要的星期，并使用左外连接，因此没有事务的周将显示0个和。请注意，在主查询中，在我执行连接的情况下，基表中的“日期”列未包含在任何类型的函数中;这允许在该列上使用索引，如果该表非常大，您应该拥有这个索引，或者如果性能可能成为其他任何原因的担忧。请注意，输出与您的不同（缺少最后一行），因为我在表格中的最后一行之前输入to-date。这是故意的，我想确保查询正常工作。另外：我没有使用“日期”或“星期”作为列名;这是一个非常糟糕的做法。保留的Oracle关键字不应该用作列名。我用“dt”和“wk”代替。

with 
    user_inputs (from_dt, to_dt) as (
     select to_date('4-Jun-2016', 'dd-Mon-yyyy'), to_date('3-Jul-2016', 'dd-Mon-yyyy') from dual 
    ), 
    test_data (dt, amt, cash, money, name) as (
     select to_date('15-Jun-2016', 'dd-Mon-yyyy'), 100, 10, 20, 'GUL' from dual union all 
     select to_date('16-Jun-2016', 'dd-Mon-yyyy'), 200, 20, 40, 'ABC' from dual union all 
     select to_date('20-Jun-2016', 'dd-Mon-yyyy'), 300, 30, 60, 'GUL' from dual union all 
     select to_date('25-Jun-2016', 'dd-Mon-yyyy'), 400, 40, 80, 'BCA' from dual union all 
     select to_date('28-Jun-2016', 'dd-Mon-yyyy'), 500, 50, 10, 'GUL' from dual union all 
     select to_date('3-Jul-2016', 'dd-Mon-yyyy'), 600, 60, 120, 'ABC' from dual union all 
     select to_date('19-Jun-2016', 'dd-Mon-yyyy'), 700, 70, 140, 'BCA' from dual union all 
     select to_date('26-Jun-2016', 'dd-Mon-yyyy'), 800, 80, 160, 'ABC' from dual union all 
     select to_date('7-Jul-2016', 'dd-Mon-yyyy'), 900, 90, 180, 'GUL' from dual union all 
     select to_date('9-Jul-2016', 'dd-Mon-yyyy'), 1000, 100, 200, 'ABC' from dual 
    ), 
    weeks (start_dt) as (
     select trunc(from_dt, 'iw') + 7 * (level - 1) 
     from user_inputs 
     connect by level <= 1 + (to_dt - trunc(from_dt, 'iw'))/7 
    ) 
select to_char(w.start_dt, 'dd-Mon-yyyy') || ' - ' || 
           to_char(w.start_dt + 6, 'dd-Mon-yyyy') as wk, 
     nvl(sum(t.amt), 0) as tot_amt, nvl(sum(t.cash), 0) as tot_cash, 
              nvl(sum(t.money), 0) as tot_money 
from weeks w left outer join test_data t 
       on t.dt >= w.start_dt and t.dt < w.start_dt + 7 
group by start_dt 
order by start_dt 
; 

输出：

WK            TOT_AMT TOT_CASH TOT_MONEY 
-------------------------------------------- ---------- ---------- ---------- 
30-May-2016 - 05-Jun-2016       0   0   0 
06-Jun-2016 - 12-Jun-2016       0   0   0 
13-Jun-2016 - 19-Jun-2016       1000  100  200 
20-Jun-2016 - 26-Jun-2016       1500  150  300 
27-Jun-2016 - 03-Jul-2016       1100  110  130 

Answer 2

您可以通过一个case语句实现这一目标：

例如

-- test data 
with data(dat, 
val1, 
val2) as 
(select sysdate - 7, 12, 13 
    from dual 
    union all 
    select sysdate - 6, 32, 1 
    from dual 
    union all 
    select sysdate - 5, 52, 53 
    from dual 
    union all 
    select sysdate - 4, 2, 16 
    from dual 
    union all 
    select sysdate - 3, 72, 154 
    from dual) 

select -- build up your groups 
     case 
     when d.dat < to_date('28.09.2016', 'DD.MM.YYYY') then 
      '<28.09.' 
     when d.dat > to_date('30.09.2016', 'DD.MM.YYYY') then 
      '>30.09.' 
     else 
      '28.-30.' 
     end as grp, 
     sum(val1), 
     sum(val2) 
    from data d 
group by case 
      when d.dat < to_date('28.09.2016', 'DD.MM.YYYY') then 
      '<28.09.' 
      when d.dat > to_date('30.09.2016', 'DD.MM.YYYY') then 
      '>30.09.' 
      else 
      '28.-30.' 
      end; 

-- output 
grp sum(val1) sum(val2) 
28.-30. 84 54 
<28.09. 12 13 
>30.09. 74 170 

要通过组日历星期使用

-- test data 
with data(dat, 
val1, 
val2) as 
(select sysdate - 9, 12, 13 
    from dual 
    union all 
    select sysdate - 6, 32, 1 
    from dual 
    union all 
    select sysdate - 5, 52, 53 
    from dual 
    union all 
    select sysdate - 4, 2, 16 
    from dual 
    union all 
    select sysdate + 3, 72, 154 
    from dual) 

select TRUNC(dat, 'iw') ||'-'|| TRUNC(dat+7, 'iw'), 
sum(val1), 
sum(val2) 
from data 
group by TRUNC(dat, 'iw') ||'-'|| TRUNC(dat+7, 'iw'); 

Answer 3

你可以试试下面的一样，我选择了13军-2016为起始日期。您可以根据您的要求选择任意日期范围。

with t as 
(select dt, 
     min(dt) over (partition by week)||' to '|| max(dt) over (partition by week) week 
from (
     select to_date('13-Jun-2016','dd-Mon-yyyy')+(level-1) dt, 
       ceil(level/7) week 
     from dual 
     connect by level<=52)) 
select week, 
     sum(amt), 
     sum(cash), 
     sum(money) 
from (
select your_table.*, 
     t.week 
from your_table,t 
where trunc(to_date(your_table.dt,'dd-Mon-yyyy'))=trunc(t.dt)) 
group by week;