的onclick提交检查PHP

Question

我有以下的PHP脚本，但它似乎为会话始终检查，因此回声出“请输入正确的密码之前，用户甚至已经进入了一个码。

我想。在之前的代码实际上火灾确实为会话和形式的岗位检查click事件怎么可以这样在PHP做

这里是我的代码：？

<?php 

session_start(); 
    if (md5($_POST['norobot']) == $_SESSION['randomnr2']) 
    { 
     // here you place code to be executed if the captcha test passes 
      echo "Code correct - email should send now"; 

} 

else { 
     // here you place code to be executed if the captcha test fails 
      echo "Code incorect please try again"; 
    } 

?> 

我的提交按钮看起来像这样：

<input type="submit" id="submit_btn" class="button" value="Submit" /> 

Answer 1

<?php 
    session_start(); 
    if (isset($_POST['norobot'])) { 
     if (md5($_POST['norobot']) == $_SESSION['randomnr2']) { 
      // here you place code to be executed if the captcha test passes 
      echo "Code correct - email should send now"; 
     } 
     else { 
      // here you place code to be executed if the captcha test fails 
      echo "Code incorect please try again"; 
     } 
    } 
?> 

Answer 2

如果你想检查会话变量设置，并具有非空值，你可以这样做：

if(isset($_SESSION['THECODE']) && $_SESSION['THECODE']!='') 
{ 
    // THECODE is set to something 
} 

=========== =

UPDATE，因为您添加代码：

<?php 

session_start(); 
if(isset($_POST['norobot']) && isset($_SESSION['randonnr2'])) 
{ 
    if (md5($_POST['norobot']) == $_SESSION['randomnr2']) 
    { 
    echo "Code correct - email should send now"; 
    } 
    else 
    { 
    echo "Code incorect please try again"; 
    } 
} 

?> 

Answer 3

为什么不这样做？检查用户是否提交了任何内容，如果不是，则不执行代码。

<?php 

session_start(); 

if(isset($_POST)) 
    if (md5($_POST['norobot']) == $_SESSION['randomnr2']) 
    { 
     // here you place code to be executed if the captcha test passes 
      echo "Code correct - email should send now"; 

} 

else { 
     // here you place code to be executed if the captcha test fails 
      echo "Code incorect please try again"; 
    } 
} 

?>