我试图创建一个表单,将图像上传到数据库并在网页上显示图像。当我上传图片时,图片会添加到数据库中,但不会显示在网页上。它只显示图像图标。我没有收到任何错误消息。这里是uploadpage.php代码:从数据库浏览器中查看图像PHP
$file = $_FILES['image']['tmp_name'];
if(!isset($file))
echo "That is not an image.";
else
{
$image = mysql_real_escape_string(file_get_contents($_FILES["image"]["tmp_name"]));
$imageName = mysql_real_escape_string($_FILES["image"]["name"]);
$imageSize = @getimagesize($_FILES['image']['tmp_name']);
if ($imageSize==FALSE)
echo "That is not an image.";
else
{
if (!$insert = mysql_query("INSERT INTO storeImage VALUES('','$imageName','$image')"))
echo "Problem Uploading Image";
else
{
$lastid = mysql_insert_id();
echo "Image Uploaded.<p/>Your image:<p/><img src=get.php?id=$lastid>";
}
}
}
而且get.php代码:
$id = mysql_real_escape_string($_REQUEST['id']);
$image = mysql_query("SELECT * FROM 'storeImage' WHERE 'id'=$id");
$image = mysql_fetch_assoc($image);
$image = $image['image'];
header("Content-type: image/jpeg");
echo $image;
非常感谢!
之类的东西你应该在你的img元素中引用你的src属性,因为它包含一个等号。 – Progrock