如何从Get-ChildItem中排除项目列表导致powershell？

Question

我想在一个路径来获得文件（实际上是大量的文件）的列表，递归，不包括某些类型：

Get-ChildItem -Path $path -Recurse | ? { $_.Name -notlike "*.cs" -and $_.Name -notlike "*.tt" } 

但我排除的一个长长的清单（仅举几例）：

Get-ChildItem -Path $path -Recurse | ? { <# what to put here ?#> } 

：

@("*.cs", "*.tt", "*.xaml", "*.csproj", "*.sln", "*.xml", "*.cmd", "*.txt") 

如何使用这种形式获得的名单？

Answer 1

这工作太：

get-childitem $path -recurse -exclude *.cs,*.tt,*.xaml,*.csproj,*.sln,*.xml,*.cmd,*.txt 

Answer 2

您可以提供排除到Get-ChildItem与-exclude参数：

$excluded = @("*.cs", "*.tt", "*.xaml", "*.csproj", "*.sln", "*.xml", "*.cmd", "*.txt") 
get-childitem -path $path -recurse -exclude $excluded 

Answer 3

这里是你将如何使用WHERE对象cmdlet做到这一点：

$exclude = @(".cs", ".tt", ".xaml", ".csproj", ".sln", ".xml", ".cmd", ".txt") 
Get-ChildItem -Path $path -Recurse | Where-Object { $exclude -notcontains $_.Extension } 

如果你不想目录在结果中返回，然后使用：

$exclude = @(".cs", ".tt", ".xaml", ".csproj", ".sln", ".xml", ".cmd", ".txt") 
Get-ChildItem -Path $path -Recurse | Where-Object { (-not $_.PSIsContainer) -and ($exclude -notcontains $_.Extension) } 

Answer 4

Set-Location C:\ 

$ExcludedcDirectory = "Windows|Program|Visual|Trend|NVidia|inet" 
$SearchThis = Get-ChildItem -Directory | where Name -NotMatch $ExcludedcDirectory 

$OutlookFiles = foreach ($myDir in $SearchThis) {  
    $Fn = Split-Path $myDir.fullname 
    $mypath = "Get-ChildItem -Path $Fn\*.pst, *.ost -Recurse -ErrorAction SilentlyContinue" 

    Invoke-Expression "$mypath" 
} 
$OutlookFiles.FullName