2016-03-15 87 views
0

我总是在控制台看到如何回报承诺风趣h动车组承诺:从多个承诺

var _addOrDeleteUser = function (userId, addToProjects, removeFromProjects) { 
    var deferred = $q.defer(); 
    var promises = []; 

    promises.push(projectResource.addUserToProjects({ userId: userId }, addToProjects, function (result) { 
     console.log("addUserToProjects"); 
     deferred.resolve(); 
     return result; 
    })); 

    promises.push(projectResource.deleteUserFromProjects({ userId: userId }, removeFromProjects, function (result) { 
     console.log("deleteUserFromProjects"); 
     deferred.resolve(); 
     return result; 
    })); 

    return $q.all(promises); 
} 
+1

你能提供这两种方法的内容,以及好吗? 'projectResource.addUserToProjects'和'projectResource.deleteUserFromProjects' –

+1

另外,你的'deferred'似乎什么都不做 - 你可以删除'var deferred = $ q.defer();'和那两个'deferred'的行。 resolve();' –

+0

你确定函数'addUserToProjects'和'deleteUserFromProjects'返回一个promise吗?附: https://jsfiddle.net/hLk0oruy/ –

回答

2

您可以使用链接的承诺为 -

travelService 
     .getDeparture(user)           // Request #1 
     .then(function(departure){ 
      $scope.departure = departure;       // Response Handler #1 
      return travelService.getFlight(departure.flightID);  // Request #2 
     }) 
     .then(function(flight){ 
      $scope.flight = flight;        // Response Handler #2 
      return weatherService.getForecast($scope.departure.date); // Request #3 
     }) 
     .then(function(weather){ 
      $scope.weather = weather;        // Response Handler #3 
     }); 

有关详细信息参见this

+0

如果我正确地理解了这个问题,我认为你的承诺链示例是正确的方法。 – stanleyxu2005

+0

正如我所理解的问题一样,OP在想为什么“teamsUpdated2”首先被记录下来,尽管在其他两个承诺都解决后它应该被链接。 –

+0

谢谢@ stanleyxu2005 –