有人可以帮助我,我想实现一个简单的PHP MySQL调查,但我坚持这一点,我如何存储用户选择的MySQL中的具体选择。PHP的Mysql单选按钮选择
如何评价你:
<table id="table1" rules="all" border="1" cellpadding="3" cellspacing="0" width="70%">
<colgroup width="70%"></colgroup>
<colgroup width="6%">
</colgroup>
<thead>
<tr align="center">
<th></th>
<th font="" style="font-size:9pt;" size="2"><b>Dissatisfied</b></th>
<th font="" style="font-size:9pt;" size="2"><b>Satisfied</b></th>
<th font="" style="font-size:9pt;" size="2"><b>Very Satisfied</b></th>
</tr>
</thead>
<tbody>
<tr align="center">
<td align="left"><font style="font-size:10pt;"><b>Technician's ability to understand the unique nature of your problem?</b></font></td>
<td><input name="satisfaction" value="Dissatisfied" type="radio"></td>
<td><input name="satisfaction" value="Satisfied" type="radio"></td>
<td><input name="satisfaction" value="Very Satisfied" type="radio"></td>
</tr>
<tr align="center">
</tbody>
</table>
[你到目前为止尝试过什么](http://whathaveyoutried.com/)?很久以前我上次见到''标签... – CodeZombie 2013-04-20 22:43:52