我需要生成一个PHP页面,以显示每个类似行项目的计数/摘要的方式显示存储在数组中的所有详细信息(来自MySQL请求)。PHP/MySQL数组与表计算总计计算
这里是从SQL查询收集(它一直结构以便通过工作组,产品代码)的示例数据集:
+----+-------------+-------------+-----------+-----------+
| ID | ProductCode | Description | Workgroup | Status |
+----+-------------+-------------+-----------+-----------+
| 2 | A123 | Coke | Finance | Ordered |
| 4 | A123 | Coke | Finance | Rejected |
| 1 | A123 | Coke | Finance | Rejected |
| 6 | B111 | Pepsi | Finance | Ordered |
| 5 | B111 | Pepsi | Finance | Rejected |
| 8 | B111 | Pepsi | Finance | Rejected |
| 10 | B112 | Fanta | Finance | Ordered |
| 42 | A123 | Coke | Management| Ordered |
| 16 | A123 | Coke | Management| Ordered |
| 11 | B112 | Fanta | Management| Rejected |
+----+-------------+-------------+-----------+-----------+
这些细节已经被存储在一个PHP数组如下:
Array
(
[0] => Array
(
[ID] => 2
[ProductCode] => A123
[Description] => Coke
[Workgroup] => Finance
[Status] => Ordered
)
[1] => Array
(
[ID] => 4
[ProductCode] => A123
[Description] => Coke
[Workgroup] => Finance
[Status] => Rejected
)
...etc
)
我需要的是将数据吐出多个由WorkGroup分隔的表格,每个产品有一个汇总行,每个单独的行项目都列在下面(它并不一定是一个html表格,只是一些HTML构造这是能够代表线 - 项目)
从我所显示的10例项,那就需要输出如下:
+--------------------------------------------------------+
| FINANCE TEAM |
+----+-------------+-------------+-----------+-----------+
| Coke Total: 3 Ordered: 1 Rejected: 2 |
+----+-------------+-------------+-----------+-----------+
| 2 | A123 | Coke | Finance | Ordered |
| 4 | A123 | Coke | Finance | Rejected |
| 1 | A123 | Coke | Finance | Rejected |
+----+-------------+-------------+-----------+-----------+
| Pepsi Total: 3 Ordered: 1 Rejected: 2 |
+----+-------------+-------------+-----------+-----------+
| 6 | B111 | Pepsi | Finance | Ordered |
| 5 | B111 | Pepsi | Finance | Rejected |
| 8 | B111 | Pepsi | Finance | Rejected |
+----+-------------+-------------+-----------+-----------+
| Fanta Total: 1 Ordered: 1 Rejected: 0 |
+----+-------------+-------------+-----------+-----------+
| 10 | B112 | Fanta | Finance | Ordered |
+----+-------------+-------------+-----------+-----------+
+--------------------------------------------------------+
| MANAGEMENT TEAM |
+----+-------------+-------------+-----------+-----------+
| Coke Total: 2 Ordered: 2 Rejected: 0 |
+----+-------------+-------------+-----------+-----------+
| 42 | A123 | Coke | Management| Ordered |
| 16 | A123 | Coke | Management| Ordered |
+----+-------------+-------------+-----------+-----------+
| Fanta Total: 1 Ordered: 0 Rejected: 1 |
+----+-------------+-------------+-----------+-----------+
| 11 | B112 | Fanta | Management| Rejected |
+----+-------------+-------------+-----------+-----------+
我可以,如果我要求不够明确的进一步阐述。
任何帮助将非常感激。
在此先感谢。
当您以“我有......且我需要......”开始发布信息时,您应该评估您是否编写了任何代码以尝试解决您的问题。 –
道歉,如果你认为我太向前。我试图解决我的问题,没有一个值得发布,因为它是完整的和完全垃圾。正如我所说的:“任何帮助都会得到很大的赞赏。” – Zam
完整和完全的垃圾更多的是与没有任何东西一起工作。如果你有什么,我们可以指出你出错的地方或者你可以做得更好的地方。 –