2015-10-12 44 views
1

我试图上传一个csv文件,然后将其内容插入到我的数据库中。我可以成功上传文件,但在插入查询中出现错误。下面的代码的一部分:PHP - fopen():无法在上传的文件上打开流

//Upload the file 
$file_path = "uploads/";  
$file_path = $file_path . basename($_FILES['uploaded_file']['name']); 
$files = pathinfo($file_path,PATHINFO_EXTENSION); 
$uploadstatus = 1; 
$found   = 0; 

if ($_SERVER["REQUEST_METHOD"] == "POST") { 
// check if the file being submitted is a csv file 
$file_type=$_FILES['uploaded_file']['type']; 
if ($files=="CSV") { 
    if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $file_path)) { 
    $uploadstatus = 1; 
    echo "<script type='text/javascript'>alert('File upload successful.')</script>"; 
} else{ 
    echo "<script type='text/javascript'>alert('File upload failed. Please check then re-upload file.')</script>"; 
} 
} 


$filename = $_FILES['uploaded_file']['name']; 
if (file_exists($file_path.$filename) && $uploadstatus) { 
    if (!$found) { 
     include('conn.php'); 

     //get the file 
     $handle = fopen($filename,"r"); 

      do { 
       if (isset($data[0])) { 
        $data0 = mysql_real_escape_string($data[0]); //rcode 
        $data1 = mysql_real_escape_string($data[1]); //pcode 
        $data2 = mysql_real_escape_string($data[2]); //mcode 
        $data3 = mysql_real_escape_string($data[3]); //bcode 
        $data4 = mysql_real_escape_string($data[4]); //ecode 
        $data5 = mysql_real_escape_string($data[5]); //filetype 
        $data6 = mysql_real_escape_string($data[6]); //rec_count 
        $data7 = mysql_real_escape_string($data[7]); //gs_count 
        $data8 = mysql_real_escape_string($data[8]); //be_count 
        $data9 = mysql_real_escape_string($data[9]); //qc_count 
        $data10 = mysql_real_escape_string($data[10]); //tt_count 
        $data11 = mysql_real_escape_string($data[11]); //rm_count 
        $data12 = mysql_real_escape_string($data[12]); //sc_count 
        $data13 = mysql_real_escape_string($data[13]); //in_count 
        $data14 = mysql_real_escape_string($data[14]); //en_count 
        $data15 = mysql_real_escape_string($data[15]); //co_count 
        $data16 = mysql_real_escape_string($data[16]); //ve_count 
        $data17 = mysql_real_escape_string($data[17]); //editing 


        $query = "INSERT INTO tbltest (rcode,pcode,mcode,bcode,ecode,filetype,rec_count,gs_count,be_count,qc_count,tt_count,rm_count,sc_count,in_count,en_count,co_count,ve_count,ed_count) 
           VALUES ('$data0','$data1','$data2','$data3','$data4','$data5','$data6','$data7','$data8','$data9','$data10','$data11','$data12','$data13','$data14','$data15','$data16','$data17') ON DUPLICATE KEY UPDATE rec_count=values(rec_count),gs_count=values(gs_count),be_count=values(be_count),qc_count=values(qc_count),tt_count=values(tt_count),rm_count=values(rm_count),sc_count=values(sc_count),in_count=values(in_count),en_count=values(en_count),co_count=values(co_count),ve_count=values(ve_count),ed_count=values(ed_count)"; 

        mysql_query ($query,$connect); 
       }  
      } while ($data = fgetcsv($handle,1000,"|")); 
     } 
    } 
} 

回声的结果是正确的文件,但我得到的是说fopen(): failed to open stream: No such file or directoryfgetcsv() expects parameter 1 to be resource, boolean given错误。

+0

可能的路径是错误的。 –

+0

我也尝试过回显整个文件+路径,并且它正确 – user3201441

+0

如果你从你的路径访问,你会得到什么? –

回答

1

你试图打开一个不存在的文件。

功能move_uploaded_file完全按照它的说法 - 它移动已上传的文件。一旦你调用了这个函数,文件就不再存在于临时上传区域。

更改该位:

$filename = $_FILES['uploaded_file']['name']; 
if (file_exists($file_path.$filename) && $uploadstatus) { 
    if (!$found) { 
     include('conn.php'); 

     //get the file 
     $handle = fopen($filename,"r"); 

到:

$filename = $file_path; 
if (file_exists($filename) && $uploadstatus) { 
    if (!$found) { 
     include('conn.php'); 

     //get the file 
     $handle = fopen($filename,"r"); 
+0

ohhh。谢谢 – user3201441

+0

值得注意的是,文件被移动到的路径应该是**绝对**路径,目前路径只是'uploads/{fiename}',这可能会导致'move_uploaded_file'问题 – Martin

-1

文件不以其原始名称存储。

这是实际的文件:

$_FILES['userfile']['tmp_name'] 

在精细的手工了解更多:

http://be2.php.net/manual/en/features.file-upload.post-method.php

+0

我已经这样做了,同样的错误 – user3201441

+0

我没有看到在你的例子中使用fgetcsv()的任何代码。 –

+0

我也没有看到任何提及的$ file_path的值。很难帮助完成这样一个不完整的代码片段。 –

相关问题