2015-09-07 54 views
1

我正在用离子创建一个应用程序,但我无法在android中模拟它以正确查看它们的功能。 运行命令时效仿 我使用Ubuntu 4.14以下是错误的Linux OS 桑丁@灵-5448:〜/项目/ soucgApp $ sudo的离子仿真机器人错误模拟android离子框架

Running command: /home/sandim/projects/soucgApp/hooks/after_prepare/010_add_platform_class.js /home/sandim/projects/soucgApp 
add to body class: platform-android 
Running command: /home/sandim/projects/soucgApp/platforms/android/cordova/run --emulator 
ERROR: Error: Failed to find 'ANDROID_HOME' environment variable. Try setting setting it manually. 
Failed to find 'android' command in your 'PATH'. Try update your 'PATH' to include path to valid SDK directory. 
Error: /home/sandim/projects/soucgApp/platforms/android/cordova/run: Command failed with exit code 2 
    at ChildProcess.whenDone (/usr/local/lib/node_modules/cordova/node_modules/cordova-lib/src/cordova/superspawn.js:139:23) 
    at ChildProcess.emit (events.js:110:17) 
    at maybeClose (child_process.js:1015:16) 
    at Process.ChildProcess._handle.onexit (child_process.js:1087:5) 

没有人知道如何解决这个?

+0

你设置'andoid_home'环境中的.bash_profile变量的联系? –

+0

'错误:错误:无法找到'ANDROID_HOME'环境变量。 “这是你的问题。 –

回答