我遇到了一个我无法解决的问题。 例如,我有与行,id,季节,情节,顺序的表。在表 数据是这样的:内部连接更新不正确
+--------+---------------+----------------+--------------+
| id | season | episode | order |
+--------+---------------+----------------+--------------+
| 153914 | 1 | 1 | NULL |
| 153915 | 1 | 3 | NULL |
| 153916 | 1 | 2 | NULL |
| 153919 | 1 | 3 | NULL |
| 153920 | 1 | 4 | NULL |
| 153921 | 1 | 3 | NULL |
+--------+---------------+----------------+--------------+
所以,当我跑不UPDATE SELECT查询,行顺序是绝对正确排序
SELECT id, season, episode, (@row:[email protected]+1) as order
FROM `shows`, (select @row:=0) as rc
WHERE `show_id`= 14670
ORDER BY CAST(season AS UNSIGNED) ASC, CAST(episode AS UNSIGNED) ASC
+--------+--------+---------+--------+
| id | season | episode | order |
+--------+--------+---------+--------+
| 153914 | 1 | 1 | 1 |
| 153916 | 1 | 2 | 2 |
| 153915 | 1 | 3 | 3 |
| 153919 | 1 | 3 | 4 |
| 153921 | 1 | 3 | 5 |
| 153920 | 1 | 4 | 6 |
+--------+--------+---------+--------+
但是,当我使用相同的查询作为UPDATE的子查询声明它不以相同的方式排序并设置不同的顺序值。
UPDATE `shows` f
JOIN
(
SELECT id, (@row:[email protected]+1) as rowOrder
FROM `shows` as Fl, (select @row:=0) as rc
WHERE Fl.`show_id` = 14670
ORDER BY Fl.season ASC, Fl.episode ASC
) t
ON t.id = f.id
SET f.order = t.rowOrder
mysql> SELECT id, season, episode, order FROM `shows` WHERE `show_id`=14670;
+--------+--------+---------+--------+
| id | season | episode | order |
+--------+--------+---------+--------+
| 153914 | 1 | 1 | 1 |
| 153915 | 1 | 3 | 2 |
| 153916 | 1 | 2 | 3 |
| 153919 | 1 | 3 | 4 |
| 153920 | 1 | 4 | 5 |
| 153921 | 1 | 3 | 6 |
+--------+--------+---------+--------+
请向我解释为什么会发生,以及如何解决它。 MySQL版本:
>mysql --version
mysql Ver 14.14 Distrib 5.7.18, for Linux (x86_64) using EditLine wrapper
这不是:-( – Strawberry