我试图将wchar *转换为字符串。首先,我把它当作wstring。当我搜索时,此方法在stackoverflow中指定。但这对我来说不起作用。它出什么问题了?如何将WCHAR *转换为C++中的字符串,反之亦然?
GetProcessImageNameFromPID.cpp
BOOL GetProcessImageNameFromPID::getProcessNameFromProcessID(DWORD processId, WCHAR**processName)
{
HANDLE hProcessSnap;
HANDLE hProcess;
PROCESSENTRY32 pe32;
DWORD dwPriorityClass;
// Take a snapshot of all processes in the system.
hProcessSnap = CreateToolhelp32Snapshot(TH32CS_SNAPPROCESS, 0);
if (hProcessSnap == INVALID_HANDLE_VALUE)
{
printError(TEXT("CreateToolhelp32Snapshot (of processes)"));
return(FALSE);
}
// Set the size of the structure before using it.
pe32.dwSize = sizeof(PROCESSENTRY32);
// Retrieve information about the first process,
// and exit if unsuccessful
if (!Process32First(hProcessSnap, &pe32))
{
printError(TEXT("Process32First")); // show cause of failure
CloseHandle(hProcessSnap); // clean the snapshot object
return(FALSE);
}
// Now walk the snapshot of processes, and
// display information about each process in turn
int i = 0;
do
{
WCHAR*allprocessName = pe32.szExeFile;
//_tprintf(TEXT("\n%d)PROCESS NAME: %s"), i, allprocessName);
// Retrieve the priority class.
dwPriorityClass = 0;
hProcess = OpenProcess(PROCESS_ALL_ACCESS, FALSE, pe32.th32ProcessID);
if (hProcess == NULL)
printError(TEXT("OpenProcess"));
else
{
dwPriorityClass = GetPriorityClass(hProcess);
if (!dwPriorityClass)
printError(TEXT("GetPriorityClass"));
CloseHandle(hProcess);
}
DWORD pid = pe32.th32ProcessID;
//_tprintf(TEXT("\n Process ID = %d"), pid);
if (pid == processId)
{
*processName = allprocessName;
//_tprintf(TEXT("Inside Method:\n"));
_tprintf(TEXT("PROCESS NAME: %s\n\n"), *processName);
return TRUE;
}
i++;
} while (Process32Next(hProcessSnap, &pe32));
CloseHandle(hProcessSnap);
return(FALSE);
}
int _tmain(int argc, _TCHAR* argv[])
{
WCHAR**processName = (WCHAR**)malloc(sizeof(WCHAR));
GetProcessImageNameFromPID::getProcessNameFromProcessID(4, processName);
_tprintf(TEXT("PROCESS NAME: %s\n\n"), *processName); // correct
GetProcessImageNameFromPID::getProcessNameFromProcessID(executionProcessID, processName);
wstring ws(*processName);
string str(ws.begin(), ws.end());
processImageName = str;
cout << processImageName << endl; // some wrong characters are printed
}
为什么要将宽字符转换为常规字符?宽字符串中任何不能用窄字符串表示的东西都会给你带来垃圾。 – NathanOliver