我如何使这个循环工作？

我应该收集数字的输入，直到用户键入'0'。当用户决定退出循环时，用户可以决定是否重新开始。如何修复我的程序？还是有另一种更有效的方式来提供这个程序？我如何使这个循环工作？

int regular, special, vip; 
int i; 
bool flag = true; 

while(flag) 
{ 
    cout << "input please: "; 
    cin >> i; 

    if ((i <10000) && (i > 0)) 
    { 
     regular++; 
    } 

    if ((i >10000) && (i<=50000)) 
    { 
     special++; 
    } 

    if (i > 50000) 
    { 
     vip++; 
    } 

    if (i==0); 
    { 
     flag = false; 
     cout << "Your branch has " << regular << " Regular Customers, " 
      << special << " Special Customers and " << vip << " VIP Customers" 
     << "Try again? [1 = yes/ 0 = no] " << endl; 
    } 
}

来源

2016-09-27 asteron9

一个良好的开端。将除去从'分号如果（I == 0）;' – paddy

@paddy OnAncientJoke：'如果（incoming_detected（））; launch_nuclear_counterstrike（）;' –

jfc我盲谢谢！ – asteron9

这应该工作。 cout之前设置flag为false。

同时删除分号后if(i==0)

int regular, special, vip; 
int i; 
bool flag = true; 

while(flag) 
{ 
    cout << "input please: "; 
    cin >> i; 

    if ((i <10000) && (i > 0)) 
    { 
     regular++; 
    } 

    if ((i >10000) && (i<=50000)) 
    { 
     special++; 
    } 

    if (i > 50000) 
    { 
     vip++; 
    } 

    if (i==0) 
    { 
     cout << "Your branch has " << regular << " Regular Customers, " 
      << special << " Special Customers and " << vip << " VIP Customers" 
      << "Try again? [1 = yes/ 0 = no] " << endl; 
     flag = false; 
    } 
}

来源

2016-09-27 05:23:30

如果我理解你的要求正确，你就必须在用户的选择读再试一次，做基础的东西。哦，并删除分号后if(i==0)：

if (i==0) 
{ 
    flag = false; 
    cout << "Your branch has " << regular << " Regular Customers, " 
     << special << " Special Customers and " << vip << " VIP Customers" 
    << "Try again? [1 = yes/ 0 = no] " << endl; 

    /* Do what the user wants */ 
    cin>> i; 
    if(i == 1) 
    { 
     /* Reset regular, special, and vip variables if desired */ 

     flag = true; 
    } 
}

来源

2016-09-27 05:22:09 kdelaney

我如何使这个循环工作？

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