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此代码适用于2.7,但不适用于3.5 - 我知道这与Unicode兼容有关。TypeError:必须是unicode字符,而不是str
这是代码的任何帮助,将不胜感激
import array
import sys
ConstNoStudents = int(4)
Counter = int(0)
StudentMarkTest1 = array.array("Test 1", range(ConstNoStudents + 1))
StudentMarkTest2 = array.array("Test 2", range(ConstNoStudents + 1))
StudentName = []
StudentGender = []
input_value = raw_input
while Counter <4:
gender_value = int(0)
input_value = raw_input
Counter = Counter+1
StudentName.append (raw_input("Please Enter Student Name "))
print(StudentName)
while gender_value == 0:
gender = raw_input("Please Enter Student Gender ")
if gender == 'm' or gender == 'f' or gender =='M' or gender == 'F':
StudentGender.append(gender)
gender_value = gender_value+1
StudentMarkTest1[Counter] = int(raw_input("Please Enter Mark for Test 1 "))
StudentMarkTest2[Counter] = int(raw_input("Please Enter Mark for Test 2 "))
print (StudentName)
print (StudentGender)
print (StudentMarkTest1)
print (StudentMarkTest2)
什么是实际的追溯? –
对于初学者来说,在Python 3中没有'raw_input'这样的东西。除此之外,您需要提供产生错误和实际错误内容的输入。 – glibdud