从JSON对象

Question

多维数组从JSON对象下

{cols:[{"id":"t","label":"Title","type":"string"},{"id":"l","label":"Avg ","type":"string"},{"id":"lb","label":"High","type":"string"},{"id":"lo","label":"Low","type":"string"}],rows:[{"c":[{"v":"Change navigation"},{"v":5.6666666666667},{"v":"10"},{"v":"1"}]},{"c":[{"v":"Executive leadership"},{"v":6.0666666666667},{"v":"7"},{"v":"3"}]},{"c":[{"v":"Business ownership"},{"v":5.8095238095238},{"v":"10"},{"v":"2"}]},{"c":[{"v":"Change enablement"},{"v":6.4285714285714},{"v":"9"},{"v":"5"}]}]} 

我怎样才能像

[['Change navigation',6.5333333333333],['Executive leadership',6.0666666666667],['Business ownership',5.8095238095238],['Change enablement',6.4285714285714]] 

有人贴出了一个维数组的代码从this.cant弄不清多维在JavaScript

var arr = [], 
i = 0; 
for (; i < json.rows.length; i++) { 
arr.push(json.rows[i].c[0].v + '=' + json.rows[i].c[1].v); 

}

这给推一个连接字符串的

['Change navigation=6.5333333333333','Executive leadership=6.0666666666667', 'Business ownership=5.8095238095238','Change enablement=6.4285714285714'] 

Answer 1

相反，推动整个数组到现有阵列：

var arr = []; 
for(var i = 0, l = json.rows.length; i < l; i++) { 
    arr.push([ json.rows[i].c[0].v, json.rows[i].c[1].v ]); 
}