1
当父状态传递给子组件更改时，我无法重新渲染组件。 MapNav组件包含的按钮触发方法改变当前显示的弹出窗口。我的问题是，当有人点击zaloguj或wyloguj，它应该工作重新渲染UserPopup按钮，但它不会做，我不能弄清楚什么是错的也是我不想触发动画时isLoggedIn状态变化还有一件事logIn方法正确地改变状态。 isLoggedIn状态只是暂时的，我将改为使用商店。我试图编写尽可能多的功能组件，但在某些情况下，我不能避免使用状态，我敢打赌，我的代码中存在问题，所以我会欣赏所有改进提示。道具变化时重新渲染功能组件
const MapNav = (props) => {
return <div className={'mapNavContainer'}>
<ul className={'navList'}>
<li><a href="#about"><i className={"glyphicon glyphicon-fullscreen"} /></a></li>
<li><a href="#about"><i className={"glyphicon glyphicon-chevron-left"} /></a></li>
<li><a href="#about"><i className={"glyphicon glyphicon-chevron-right"} /></a></li>
<li><a href="#about"><i className={"glyphicon glyphicon-map-marker"} /></a></li>
<li><a href="#" onClick={props.onUserIconClick}><i className={"glyphicon glyphicon-user"} /></a></li>
<li><a href="#" onClick={props.onInfoClick}><i className={"glyphicon glyphicon-info-sign"} /></a></li>
</ul>
</div>
}
const UserPopup = (props) => {
return <div>
{(props.isLoggedIn) ? (
<div className={'navPopups col-sm-3 panel panel-default'}>
<div className={"panel-heading"}>Zalogowany</div>
<div className={"panel-body"}>
<button type='submit' onClick={props.logIn}>wyloguj</button>
</div>
</div>
) : (
<div className={'navPopups col-sm-3 panel panel-default'}>
<div className={"panel-heading"}>Niezalogowany</div>
<div className={"panel-body"}>
<button type='submit' onClick={props.logIn}>Zaloguj</button>
</div>
</div>
)
}
</div>;
};
function Welcome(props) {
return <div className={'navPopups col-sm-3 panel panel-default'}>
<div className={"panel-heading"}>Informacje o Autorze.</div>
<div className={"panel-body"}>
Basic panel example
</div>
</div>;
}
class MapHeader extends React.Component {
constructor(props) {
super(props);
this.state = {
currentPopup: null,
isLoggedIn: false,
username: '[email protected]',
};
this.onInfoClick = this.onInfoClick.bind(this);
this.onUserIconClick = this.onUserIconClick.bind(this);
this.logIn = this.logIn.bind(this);
}
onInfoClick = (e) => {
e.preventDefault();
this.setPopup(<Welcome />);
}
onUserIconClick = (e) => {
e.preventDefault();
const loginPopup = <UserPopup isLoggedIn={this.state.isLoggedIn} username={this.state.username} logIn={this.logIn} />;
this.setPopup(loginPopup);
}
setPopup = (obj) => {
this.state.currentPopup === null ? this.setState({ currentPopup: obj }) : this.setState({ currentPopup: null });
}
logIn = (e) => {
this.setState({ isLoggedIn: !this.state.isLoggedIn });
}
render() {
return (
<nav className={'header'}>
<div className={'container-fluid'}>
<div className={"navbar-header"}>
<button type="button" className={"navbar-toggle collapsed"} data-toggle="collapse" data-target="#navbar" aria-expanded="false" aria-controls="navbar">
<span className={"sr-only"}>Toggle navigation</span>
<span className={"icon-bar"} />
<span className={"icon-bar"} />
<span className={"icon-bar"} />
</button>
</div>
<div id={"navbar"} className={'navContainer'}>
{MapNav({onInfoClick:this.onInfoClick, onUserIconClick:this.onUserIconClick})}
{this.state.currentPopup ? this.state.currentPopup : null}
</div>
</div>
</nav>
)
}
}
// Render it
ReactDOM.render(
<MapHeader />,
document.getElementById("react")
);<div id="react"></div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/latest/css/bootstrap.min.css" />
边注：'的className = { “面板标题”}'可以更简单地被写入'的className = “面板标题”'。当值是一个简单的字符串时，不需要'{}'。 –
谢谢你的提示，我也加了runnable – habibi07
注意事项2：你的'logIn'等是关闭'this'的箭头函数。对它们调用'bind'将不会做任何改变它的'this'（但它已经是正确的了，所以你不需要'bind'）。 –