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您能否帮我弄清楚如何使用if语句向不同类型的用户显示不同的内容。登录php代码,管理员/用户的不同内容:
这是我已经在另一个问题找到的代码:
if($_SESSION['usertype'] == 2){ //do stuff here} if ($_SESSION['usertype']) == 1) { //do stuff here }
我想利用这个页面上只有会员可以浏览网页,并根据用户类型,它应该表现出不同的内容。
但是我不能发送用户类型中,当用户登录时的登录页面,这是(login.php中)使用有代码:
<?php
// First we execute our common code to connection to the database and start the session
require("common.php");
// This variable will be used to re-display the user's username to them in the
// login form if they fail to enter the correct password. It is initialized here
// to an empty value, which will be shown if the user has not submitted the form.
$submitted_username = '';
// This if statement checks to determine whether the login form has been submitted
// If it has, then the login code is run, otherwise the form is displayed
if(!empty($_POST))
{
// This query retreives the user's information from the database using
// their username.
$query = "
SELECT
id,
username,
password,
salt,
email
usertype
FROM users
WHERE
username = :username
";
// The parameter values
$query_params = array(
':username' => $_POST['username']
);
try
{
// Execute the query against the database
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch(PDOException $ex)
{
// Note: On a production website, you should not output $ex->getMessage().
// It may provide an attacker with helpful information about your code.
die("Failed to run query: " . $ex->getMessage());
}
// This variable tells us whether the user has successfully logged in or not.
// We initialize it to false, assuming they have not.
// If we determine that they have entered the right details, then we switch it to true.
$login_ok = false;
// Retrieve the user data from the database. If $row is false, then the username
// they entered is not registered.
$row = $stmt->fetch();
if($row)
{
// Using the password submitted by the user and the salt stored in the database,
// we now check to see whether the passwords match by hashing the submitted password
// and comparing it to the hashed version already stored in the database.
$check_password = hash('sha256', $_POST['password'] . $row['salt']);
for($round = 0; $round < 65536; $round++)
{
$check_password = hash('sha256', $check_password . $row['salt']);
}
if($check_password === $row['password'])
{
// If they do, then we flip this to true
$login_ok = true;
}
}
// If the user logged in successfully, then we send them to the private members-only page
// Otherwise, we display a login failed message and show the login form again
if($login_ok)
{
// Here I am preparing to store the $row array into the $_SESSION by
// removing the salt and password values from it. Although $_SESSION is
// stored on the server-side, there is no reason to store sensitive values
// in it unless you have to. Thus, it is best practice to remove these
// sensitive values first.
unset($row['salt']);
unset($row['password']);
// This stores the user's data into the session at the index 'user'.
// We will check this index on the private members-only page to determine whether
// or not the user is logged in. We can also use it to retrieve
// the user's details.
$_SESSION['user'] = $row;
$_SESSION['usertype'] = $row;
// Redirect the user to the private members-only page.
header("Location: dashboard.php");
die("Redirecting to: dashboard.php");
}
else
{
// Tell the user they failed
print("Login Failed.");
// Show them their username again so all they have to do is enter a new
// password. The use of htmlentities prevents XSS attacks. You should
// always use htmlentities on user submitted values before displaying them
// to any users (including the user that submitted them). For more information:
// http://en.wikipedia.org/wiki/XSS_attack
$submitted_username = htmlentities($_POST['username'], ENT_QUOTES, 'UTF-8');
}
}
?>
什么改变,我需要做在这个代码中? 我对这一切都很陌生,任何帮助表示赞赏。
你为什么两次设置相同的变量$ _SESSION – 2013-12-17 17:10:43
你为什么user'和'usertype'设置'同一个变量? –
“$ _SESSIONN ['usertype'] = $ row;”这只是我试图弄清楚,我应该用什么来代替?感谢您的及时回应 – user3112117