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我有Android的JSON从MySQL解析一个问题,当我尝试执行我的项目,它告诉我“输入的字符0 org.json.jsonexception结束” 这是我的解析代码:如何解析json?
protected String doInBackground(String... arg0) {
for(String url: arg0){
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
HttpResponse response = httpclient.execute(httppost);
inp = response.getEntity().getContent();
}
catch (ClientProtocolException e){
error = "ClientProtocolException: " + e.getMessage();
}catch (IOException e){
error = "ClientProtocolException: " + e.getMessage();
}
}
BufferedReader reader;
try{
reader = new BufferedReader(new InputStreamReader(inp, "iso-8859-1"),8);
String line=null;
while ((line = reader.readLine()) != null){
txt += line+"\n";
}
inp.close();
}catch (UnsupportedEncodingException e){
error = "Unsupport Encoding: "+e.getMessage();
}catch (IOException e){
error = "Error IO: "+e.getMessage();
}
list1 = new ArrayList<Pharm>();
try{
JSONArray jArray = new JSONArray(txt);
for(int i=0;i<jArray.length();i++){
JSONObject jsonData = jArray.getJSONObject(i);
Pharm pharm = new Pharm();
pharm.setNomPharm(jsonData.getString("nomPharm"));
pharm.setAdressePharm(jsonData.getString("adressePharm"));
list1.add(pharm);
}
}catch (JSONException e){
error = "Error convert to JSON or Error JSON format: "+ e.getMessage();
}
return error;
}
我需要你的帮助。
你能告诉我们'JSON'回来了? –
这将是一个** **必须为我们解决这个问题... – Vucko
{ 药店:[{ idPharm: “1”, nomPharm: “pharm1”, adressePharm: “干草萨达”, lat:“ssssssss”, lon:“ddddddddd” } ] } –