SELECT DISTINCT HAVING计算唯一条件

Question

我已经在此搜索了一个答案，但无法找到相当多的方式根据条件获取此不同的记录集。我有一个表下面的示例数据：

 
+---------+-------------+ 
| Branch | Task Status | 
+---------+-------------+ 
| Account | Completed | 
| HR  | Completed | 
| Account | Completed | 
| HR  | Not Define | 
| Account | Uncompleted | 
| Account | Not Define | 
| Account | Completed | 
| HR  | Uncompleted | 
| HR  | Uncompleted | 
| HR  | Completed | 
| HR  | Not Define | 
+---------+-------------+ 

我想创建一个查询，显示总任务的数量，还希望总任务状态的任务的明智号码，例如

Branch Total Task Completed Uncompleted Not Define 
Account  5   3  1   1 
Admin   6   2  2   2 

Answer 1

SELECT Branch 
    , COUNT(1) as Total 
    , COUNT(CASE WHEN TaskStatus = 'Completed' THEN 1 ELSE 0 END) AS Completed 
    , COUNT(CASE WHEN TaskStatus = 'Uncompleted' THEN 1 ELSE 0 END) AS Uncompleted 
    , COUNT(CASE WHEN TaskStatus = 'Not Define' THEN 1 ELSE 0 END) AS NotDefine 
FROM Table 
GROUP BY Branch 

Answer 2

SELECT branch, 
     COUNT(*), 
     SUM(CASE status WHEN 'completed' THEN 1 END) AS completed, 
     SUM(CASE status WHEN 'uncompleted' THEN 1 END) AS uncompleted, 
     SUM(CASE status WHEN 'not define' THEN 1 END) AS not_define 
FROM task 
GROUP BY 
     branch 

Answer 3

SELECT branch, 
COUNT(*), 
COUNT(CASE taskstatus WHEN 'Completed' THEN 1 END), 
COUNT(CASE taskstatus WHEN 'Uncompleted' THEN 1 END), 
COUNT(CASE taskstatus WHEN 'Not Define' THEN 1 END) 
FROM YourTable 
GROUP BY branch; 

Answer 4

试试这个

SELECT * FROM (SELECT 
ROW_NUMBER() OVER(PARTITION BY Branch ORDER BY [Task Status]) AS No, 
Branch, 
sum (CASE WHEN [Task Status] = 'Completed' THEN 1 ELSE 0 END) OVER (PARTITION BY Branch) AS [Completed], 
sum (CASE WHEN [Task Status] = 'Not Define' THEN 1 ELSE 0 END) OVER (PARTITION BY Branch) AS [Not Define], 
sum (CASE WHEN [Task Status] = 'Uncompleted' THEN 1 ELSE 0 END) OVER (PARTITION BY Branch) AS [Uncompleted] 
FROM task) AS T1 WHERE No = 1 

或

SELECT * FROM (SELECT 
ROW_NUMBER() OVER(PARTITION BY Branch ORDER BY [Task Status]) AS No, 
Branch, 
count (CASE WHEN [Task Status] = 'Completed' THEN 1 ELSE 0 END) OVER (PARTITION BY Branch) AS [Completed], 
count (CASE WHEN [Task Status] = 'Not Define' THEN 1 ELSE 0 END) OVER (PARTITION BY Branch) AS [Not Define], 
count (CASE WHEN [Task Status] = 'Uncompleted' THEN 1 ELSE 0 END) OVER (PARTITION BY Branch) AS [Uncompleted] 
FROM task) AS T1 WHERE No = 1 

Answer 5

在SQL Server2005中+你可以使用PIVOT操作

SELECT * 
FROM (
     SELECT *, COUNT(*) OVER(PARTITION BY Branch) AS TotalTask 
     FROM dbo.task 
    ) p  
PIVOT 
(
    COUNT(p.Task) FOR p.Task IN ([Completed], [Uncompleted], [Not Define]) 
) x 

上SQLFiddle